- #1

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how to integ 2x^2 / (1-x^2)

using partial fracton??

using partial fracton??

- Thread starter teng125
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- #1

- 416

- 0

how to integ 2x^2 / (1-x^2)

using partial fracton??

using partial fracton??

- #2

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ah....i forgot to type the answer=-2x + ln(1+x) - ln(1-x)

- #3

HallsofIvy

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[tex]\frac{2x^{2}}{1-x^{2}} = \frac{2x^{2}-2+2}{1-x^{2}} = \frac{-2(1-x^{2})}{1-x^{2}} +\frac{2}{1-x^{2}} = -2 +\frac{2}{1-x^{2}}[/tex]

Now use partial fractions on the second term to get your answer.

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