How to integrate (ln x)(squared)

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SUMMARY

The discussion focuses on the integration of the function (ln x)². The solution provided utilizes integration by parts, specifically the formula ∫v du = uv - ∫u dv. The final result is expressed as ∫(ln x)² dx = x(ln x)² - 2∫ln x dx, where ∫ln x dx is further simplified to x ln x - x. This method effectively breaks down the integration process for this logarithmic function.

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  • Basic knowledge of calculus, including definite and indefinite integrals.
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Hi,

I've been struggling with this problem for hours, so I was wondering if someone here could help me out, thanks:

The problem is:

How to integrate: (ln x)(to the power of 2)

Thanks
 
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Curious6 said:
Hi,

I've been struggling with this problem for hours, so I was wondering if someone here could help me out, thanks:

The problem is:

How to integrate: (ln x)(to the power of 2)

Thanks
[tex]\int\left(\ln{x}\right)^{2}\,dx=x\left(\ln{x}\right)^{2}-2\int\ln{x}\,dx[/tex]

[tex]\int\ln{x}\,dx=x\ln{x}-x[/tex]

I just used part-integration:

[tex]\int v\,du=uv-\int u\,dv[/tex]

...You should be able to put it together from here.
 
Ok, I understand now, thanks :biggrin: :-p
 

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