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How to integrate tan x/ (1 - cos x) ?

  1. Sep 6, 2007 #1
    Im doing a differential equation and end up with my last step, which is an integration.

    I can't seem to remember how to integrate this one

    int. (tanx)/(1-cosx)


    [(sinx)/(cosx)] / (1-cosx)

    u = cosx
    du = -sinx dx

    throw a negative outside the integral.


    maby? then use some easy partial frac. decomp.

    would that be a correct method to use or is there another way.

  2. jcsd
  3. Sep 6, 2007 #2


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    Staff Emeritus
    Science Advisor

    Partial fractions is the method I'd use.
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