How to integrate tan x/ (1 - cos x) ?

[robierob12]

Im doing a differential equation and end up with my last step, which is an integration.

I can't seem to remember how to integrate this one


int. (tanx)/(1-cosx)

hmmm

[(sinx)/(cosx)] / (1-cosx)

u = cosx
du = -sinx dx

throw a negative outside the integral.


du/(u)(1-u)

maby? then use some easy partial frac. decomp.

would that be a correct method to use or is there another way.


Rob

 

[cristo]

Partial fractions is the method I'd use.