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## Homework Statement

Hi, i don't really know how I should go about this question. please help me.

Question:

Integrate the following equation:

I = (integration sign from 0 to 2 sqrt3) (x^3)/(16-x^2)^(1/2)

## Homework Equations

## The Attempt at a Solution

I tried to assign u and dv initially like this:

u = (16-x^2)^(1/2)

du = -(16-x^2)^(-1/2) dx

dv = x^3 dx

v = (1/4)(x^4)

so uv - (INT)vdu

= (1/4)(16-x^2)(x^4) + (1/4)(INT)(x^4)/(16-x^4)^(1/2) dx

but it gets more complicated because of x^4, if x^3 in the integration then i could have assigned it as I and then solve it easily, but i think i made a huge mistake somewhere to get it to be like this.