Hi, i don't really know how I should go about this question. please help me.
Integrate the following equation:
I = (integration sign from 0 to 2 sqrt3) (x^3)/(16-x^2)^(1/2)
The Attempt at a Solution
I tried to assign u and dv initially like this:
u = (16-x^2)^(1/2)
du = -(16-x^2)^(-1/2) dx
dv = x^3 dx
v = (1/4)(x^4)
so uv - (INT)vdu
= (1/4)(16-x^2)(x^4) + (1/4)(INT)(x^4)/(16-x^4)^(1/2) dx
but it gets more complicated because of x^4, if x^3 in the integration then i could have assigned it as I and then solve it easily, but i think i made a huge mistake somewhere to get it to be like this.