How to integrate this? quick question

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The discussion centers on integrating the expression \(\int_{0}^{2 \lambda} \cos({\frac{kx}{2}}) \cos({nx}) dx\) as part of computing the Fourier series for the function \(f(x) = A\cos({\frac{\pi x}{\lambda}})\). The user expresses a preference to avoid using the trigonometric identity \(\cos{\alpha}\cos{\beta} = \frac{1}{2}[\cos(\alpha + \beta) + \cos{(\alpha - \beta)}]\) for the integration process. Another participant corrects the user’s identity and provides the correct form, emphasizing the importance of accurate trigonometric identities in solving integration problems.

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[tex]\int_{0}^{2 \lambda} \cos({\frac{kx}{2}}) \cos({nx}) dx[/tex]

I can't find my calc2 notes and it's killing me! This thing came up half way through the computation of the Fourier series of [tex]f(x) = A\cos({\frac{\pi x}{\lambda}})[/tex]..and i can't remember how to do it!

I am very aware of the trig identity below, but i would prefer not to use it for obvious reasons.

[tex]\cos{\alpha}\cos{\beta} = \frac{1}{2}[\cos{\frac{(\alpha + \beta)}{2} + \cos{\frac{(\alpha - \beta)}{2}][/tex]

I have the exact same question except instead of two cosines there's one cosine and one sine..any help is appreciated!
 
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What are the obvious reasons? I would think that using that identity would be the "obvious" way to do it!

(Your identity is wrong: there is no 1/2 inside the functions. It is
[tex]\cos{\alpha}\cos{\beta} = \frac{1}{2}[\cos(\alpha + \beta) + \cos{(\alpha - \beta)][/tex])

And
[tex]sin(\alpha)cos(\beta)= \frac{1}{2}[sin(\alpha+ \beta)+ sin(\alpha-\beta)][/tex]
 

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