How to know which variable comes first in the Jacobian?

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The discussion revolves around finding the Jacobian of the transformation defined by x = e^{-r}sinθ and y = e^rcosθ. Participants express confusion about how to choose variables u and v for the Jacobian calculation, noting differing results based on the order of these variables. It is clarified that the absolute value of the Jacobian determinant remains the same regardless of the order of u and v, as changing the order only affects the sign. Both the original poster and the textbook are noted to have made errors in their calculations. Ultimately, the absolute value of the Jacobian determinant is confirmed to be |sin²θ - cos²θ|, indicating that the order of variables does not impact the final result.
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Homework Statement


Find the Jacobian of the transformation:

x = e^{-r}sinθ , y = e^rcosθ

Homework Equations

The Attempt at a Solution


formula for Jacobian is absolute value of the determinant

<br /> <br /> \begin{vmatrix}<br /> \frac {∂x}{∂u} &amp; \frac {∂x}{∂v}\\<br /> \frac {∂y}{∂u} &amp; \frac {∂y}{∂v}\\<br /> \end{vmatrix}

But how am I suppose to know which one set u and v = to?

For example, if u = r and v = θ, my answer is (sinθ)^2 - (cosθ)^2 which is my books answer, which is different then when u = θ and v = r, where the answer is (cosθ)^2 - (sinθ)^2
 
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Rijad Hadzic said:

Homework Statement


Find the Jacobian of the transformation:

x = e^{-r}sinθ , y = e^rcosθ

Homework Equations

The Attempt at a Solution


formula for Jacobian is absolute value of the determinant

<br /> <br /> \begin{vmatrix}<br /> \frac {∂x}{∂u} &amp; \frac {∂x}{∂v}\\<br /> \frac {∂y}{∂u} &amp; \frac {∂y}{∂v}\\<br /> \end{vmatrix}

But how am I suppose to know which one set u and v = to?

For example, if u = r and v = θ, my answer is (sinθ)^2 - (cosθ)^2 which is my books answer, which is different then when u = θ and v = r, where the answer is (cosθ)^2 - (sinθ)^2

Since you've defined the Jacobian as the absolute value of the determinant, it doesn't matter. Those answers have the same absolute value. Changing sign is what happens in general when you interchange rows or columns of a matrix.
 
Last edited:
Rijad Hadzic said:

Homework Statement


Find the Jacobian of the transformation:

x = e^{-r}sinθ , y = e^rcosθ

Homework Equations

The Attempt at a Solution


formula for Jacobian is absolute value of the determinant

<br /> <br /> \begin{vmatrix}<br /> \frac {∂x}{∂u} &amp; \frac {∂x}{∂v}\\<br /> \frac {∂y}{∂u} &amp; \frac {∂y}{∂v}\\<br /> \end{vmatrix}

But how am I suppose to know which one set u and v = to?

For example, if u = r and v = θ, my answer is (sinθ)^2 - (cosθ)^2 which is my books answer, which is different then when u = θ and v = r, where the answer is (cosθ)^2 - (sinθ)^2

You and the book are both mistaken. The absolute value of the Jacobian determinant is ##|\sin^2 \theta - \cos^2 \theta|##, so the order does not matter.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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