How to know which variable comes first in the Jacobian?

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SUMMARY

The discussion centers on calculating the Jacobian for the transformation defined by x = e^{-r}sinθ and y = e^rcosθ. Participants explore how to assign variables u and v, with examples showing that setting u = r and v = θ yields the same absolute value for the Jacobian determinant as setting u = θ and v = r. The key conclusion is that the absolute value of the Jacobian determinant, given by |sin²θ - cos²θ|, remains unchanged regardless of the order of u and v.

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  • Understanding of Jacobian determinants
  • Familiarity with partial derivatives
  • Knowledge of transformation variables in calculus
  • Basic trigonometric identities
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  • Study the properties of Jacobian determinants in multivariable calculus
  • Learn about transformations in polar coordinates
  • Explore applications of Jacobians in change of variables for integrals
  • Investigate the relationship between matrix row operations and determinant values
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Students studying multivariable calculus, mathematicians working with transformations, and educators teaching Jacobian concepts.

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Homework Statement


Find the Jacobian of the transformation:

x = e^{-r}sinθ , y = e^rcosθ

Homework Equations

The Attempt at a Solution


formula for Jacobian is absolute value of the determinant

<br /> <br /> \begin{vmatrix}<br /> \frac {∂x}{∂u} &amp; \frac {∂x}{∂v}\\<br /> \frac {∂y}{∂u} &amp; \frac {∂y}{∂v}\\<br /> \end{vmatrix}

But how am I suppose to know which one set u and v = to?

For example, if u = r and v = θ, my answer is (sinθ)^2 - (cosθ)^2 which is my books answer, which is different then when u = θ and v = r, where the answer is (cosθ)^2 - (sinθ)^2
 
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Rijad Hadzic said:

Homework Statement


Find the Jacobian of the transformation:

x = e^{-r}sinθ , y = e^rcosθ

Homework Equations

The Attempt at a Solution


formula for Jacobian is absolute value of the determinant

<br /> <br /> \begin{vmatrix}<br /> \frac {∂x}{∂u} &amp; \frac {∂x}{∂v}\\<br /> \frac {∂y}{∂u} &amp; \frac {∂y}{∂v}\\<br /> \end{vmatrix}

But how am I suppose to know which one set u and v = to?

For example, if u = r and v = θ, my answer is (sinθ)^2 - (cosθ)^2 which is my books answer, which is different then when u = θ and v = r, where the answer is (cosθ)^2 - (sinθ)^2

Since you've defined the Jacobian as the absolute value of the determinant, it doesn't matter. Those answers have the same absolute value. Changing sign is what happens in general when you interchange rows or columns of a matrix.
 
Last edited:
Rijad Hadzic said:

Homework Statement


Find the Jacobian of the transformation:

x = e^{-r}sinθ , y = e^rcosθ

Homework Equations

The Attempt at a Solution


formula for Jacobian is absolute value of the determinant

<br /> <br /> \begin{vmatrix}<br /> \frac {∂x}{∂u} &amp; \frac {∂x}{∂v}\\<br /> \frac {∂y}{∂u} &amp; \frac {∂y}{∂v}\\<br /> \end{vmatrix}

But how am I suppose to know which one set u and v = to?

For example, if u = r and v = θ, my answer is (sinθ)^2 - (cosθ)^2 which is my books answer, which is different then when u = θ and v = r, where the answer is (cosθ)^2 - (sinθ)^2

You and the book are both mistaken. The absolute value of the Jacobian determinant is ##|\sin^2 \theta - \cos^2 \theta|##, so the order does not matter.
 

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