How to lift water out of a pool

  • Thread starter Thread starter TheStig
  • Start date Start date
  • Tags Tags
    Lift Water
Click For Summary
SUMMARY

The discussion focuses on calculating the work required to lift water out of a pool, specifically a right circular cylinder with a diameter of 20m and a height of 4m, containing water at a depth of 3.5m. The correct approach involves using the formula for work, W = ∫(density × gravity × volume) dy, leading to the conclusion that the total work needed is approximately 24,740,002 joules. The integration method is essential for accurately determining the work done against gravitational force, with the weight density of water being 9,800 N/m³.

PREREQUISITES
  • Understanding of calculus, specifically integration techniques.
  • Familiarity with the concepts of potential energy and work in physics.
  • Knowledge of density and its application in calculating mass.
  • Basic geometry of right circular cylinders.
NEXT STEPS
  • Study the application of integration in physics problems, particularly in calculating work.
  • Learn about potential energy and its relationship with mass and height in gravitational fields.
  • Explore the concept of weight density and its implications in fluid mechanics.
  • Review the derivation and application of the work formula in various contexts.
USEFUL FOR

Students in calculus and physics courses, particularly those tackling problems involving work and energy in fluid systems, as well as educators seeking to enhance their teaching methods in these subjects.

TheStig
Messages
5
Reaction score
0

Homework Statement


given, diameter and height of pool, depth of water, density of water and gravitational acceleration.
g = 9.8
height is 4m
2r = 20m
depth of water = 3.5m
density =1000kg/m^3
So, I'm supposed to find how much work is needed in joules to lift the water out of the pool.

Homework Equations


could I use density times gravity times volume to get my force?
is my distance for my water to travel 4.5m?


The Attempt at a Solution


Anyways, I've tried to use my volume for the pool and the volume I have of water * density *gravity to come up with my force and then used 4.5m as my distance to come up with my work needed to lift water out of a pool. I ended up with 1.08E7 joules but that's incorrect so any help would be appreciated.

BTW, this is a cal 2 problem/integration problem
 
Physics news on Phys.org
if it is a cal2/integration problem why aren't you doing any integration? do you know the formula for work?
 
Use the volume of the water and the density to get mass. It would appear that the pool is a right circular cyliner.

Rasining a mass m some distance h in a gravity field producing a local acceleration g increases the potential energy by mgh.
could I use density times gravity times volume to get my force?
Yes

is my distance for my water to travel 4.5m?
Well that depends, if one is lifting the CM of the pool water 4 m or (4 m + 1.75 m) or 5.75 m, which is 4 m from the top of the pool.
 
I've tried integrating it and I've tried astronuc's advice with no success, any ideas?
 
Last edited:
I'm retarded, integration works. Alright, so with a mixture of the advice, correct answer is 2474002 joules. Thanks again fellas.
 
weight density = 9800 N/m^3

work = integral {0 to 3.5} (9800)(pi*10^2)(4 - y)dy

work = 2.4 * 10^7 Joules
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
37
Views
3K
Replies
1
Views
3K
Replies
4
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
13
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K