How to parameterize solid of revolution?

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SUMMARY

The discussion focuses on parameterizing a solid of revolution defined by the piecewise function consisting of the equations (x-2)² + z² = 1 for 1 < x < 2, z = -x + 3 for 2 < x < 3, and z = x - 3 for 2 < x < 3. The user successfully parameterizes the circular arc using x = 2 + cos(θ) and z = sin(θ) for θ in [π/2, 3π/2]. The rotation about the z-axis is achieved by transforming the coordinates to x = (2 + cos(θ))cos(α), y = (2 + cos(θ))sin(α), and z = sin(θ) as α varies from 0 to 2π. The discussion concludes that this method effectively allows for the calculation of the surface area of the solid of revolution.

PREREQUISITES
  • Understanding of solid of revolution concepts in calculus
  • Familiarity with parameterization of curves
  • Knowledge of piecewise functions
  • Basic skills in trigonometric functions and transformations
NEXT STEPS
  • Learn about surface area calculations for solids of revolution using integral calculus
  • Explore advanced parameterization techniques for complex surfaces
  • Study the application of polar coordinates in three-dimensional space
  • Investigate numerical methods for approximating surface areas of irregular solids
USEFUL FOR

Students studying calculus, particularly those focusing on multivariable calculus and geometry, as well as educators seeking to enhance their teaching methods for parameterization and surface area concepts.

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Homework Statement



Here is the surface I need to parameterize. It is a solid of revolution.

58wDQ.png




Homework Equations





The Attempt at a Solution



So since its a piecewise function, I can define it as follows

(x-2)^2 + z^2 = 1, 1<x<2
z = -x+3, 2<x<3
z = x-3, 2<x<3

I know the formula for the area for a solid of revolution, but how do I parameterize this surface and then use that to calculate the surface area? I'm lost.
 
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I'll show you how to parameterize one piece. That should get you started. I would express the circular arc like this:$$
x=2+\cos\theta,\ z = \sin\theta,\ \frac \pi 2\le \theta\le\frac{3\pi} 2$$Now if you rotate that about the z axis, that will change the ##x## and ##y## values:$$
x=(2+\cos\theta)\cos\alpha,\ y=(2+\cos\theta)\sin\alpha,\ z=\sin\theta$$Now if you let ##\alpha## very from ##0## to ##2\pi##, that will get the curved portion.

That's the general method. But if you don't have to do it that way, a probably simpler method would be to just rotate the ds arc elements around.
 

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