meBigGuy
Gold Member
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It is not completely clear to me yet what you really want to do.
1. Limit the current to 10A "cleanly". That is, drop the voltage smoothly such that the max load current is always 10A. (that also means the voltage will naturally increase to maintain 10A as the load reduces)
OR
2. Cutout at 10A (seems to be what you are suggesting, but not what I think you really want). If you do this, how will decide when to turn back on.
I think old 3-relay style voltage regulators increased/reduced the field current quickly, which the battery smoothed.
But, you don't have a field winding or a battery.
The rest of this assumes scenario 1, a clean current limit:
I'm assuming you cannot vary the RPM or the field, so you are limited to something in series with the generator to limit the current.
A buck converter would be the most efficient. but it isn't a trivial design for 70V input and 10A current limit. If you were 80% efficient, limiting at 30V @ 10A out (300W) would require 360W in, so you would dissipate 60W. If it was 60V @ 10A = 600W out then at 80% efficiency you need to dissipate 120W. You may be able to get much better than 80%. I just chose 80% to illustrate the basic principles.
There may be commercial units that will do what you want, but I have not searched.
A linear current limit (of any kind) would need to dissipate "a bit" of power. Say you have 70 volts at the generator and you need to linearly reduce the voltage to 30V to keep the load at 10A. That would mean you need to dissipate 40V @ 10A which is 400 watts. That's a pretty hefty design. (if you need 60V @ 10A it would only dissipate 100W).
With a linear approach, the more you need to drop @ 10A, the more power you need to dissipate.
1. Limit the current to 10A "cleanly". That is, drop the voltage smoothly such that the max load current is always 10A. (that also means the voltage will naturally increase to maintain 10A as the load reduces)
OR
2. Cutout at 10A (seems to be what you are suggesting, but not what I think you really want). If you do this, how will decide when to turn back on.
I think old 3-relay style voltage regulators increased/reduced the field current quickly, which the battery smoothed.
But, you don't have a field winding or a battery.
The rest of this assumes scenario 1, a clean current limit:
I'm assuming you cannot vary the RPM or the field, so you are limited to something in series with the generator to limit the current.
A buck converter would be the most efficient. but it isn't a trivial design for 70V input and 10A current limit. If you were 80% efficient, limiting at 30V @ 10A out (300W) would require 360W in, so you would dissipate 60W. If it was 60V @ 10A = 600W out then at 80% efficiency you need to dissipate 120W. You may be able to get much better than 80%. I just chose 80% to illustrate the basic principles.
There may be commercial units that will do what you want, but I have not searched.
A linear current limit (of any kind) would need to dissipate "a bit" of power. Say you have 70 volts at the generator and you need to linearly reduce the voltage to 30V to keep the load at 10A. That would mean you need to dissipate 40V @ 10A which is 400 watts. That's a pretty hefty design. (if you need 60V @ 10A it would only dissipate 100W).
With a linear approach, the more you need to drop @ 10A, the more power you need to dissipate.