How to Prove log[(x-y)/3] = 1/2(logx+logy) Equals x^2+y^2=11xy?

[phy_]

show how log [(x-y)/3]=1/2(logx+logy) is equal to xsquared+ysquared=11xy

does anyone know how to solve this.
i have tried all kinds of ways though none of them seem to work.
any help would be very much appreciated!

 

[nvn]

What if you multiply both sides by 2? After that, use properties of logarithms and exponentials to solve the problem. Study properties of logarithms in your textbook, or even on-line. List relevant equations, and show your work.

 

[phy_]

Thank-you. Question has been solved.