How to Prove log[(x-y)/3] = 1/2(logx+logy) Equals x^2+y^2=11xy?

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The equation log[(x-y)/3] = 1/2(logx + logy) can be transformed into the quadratic equation x² + y² = 11xy. To prove this, one must first multiply both sides of the logarithmic equation by 2, then apply properties of logarithms and exponentials. This approach leads to a simplification that reveals the relationship between the two expressions. Understanding these transformations is crucial for solving similar logarithmic equations.

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show how log [(x-y)/3]=1/2(logx+logy) is equal to xsquared+ysquared=11xy

does anyone know how to solve this.
i have tried all kinds of ways though none of them seem to work.
any help would be very much appreciated!
 
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What if you multiply both sides by 2? After that, use properties of logarithms and exponentials to solve the problem. Study properties of logarithms in your textbook, or even on-line. List relevant equations, and show your work.
 
Thank-you. Question has been solved.
 

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