How to Prove the Commutator Relation for Quantum Spin Operators?

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Homework Help Overview

The discussion revolves around proving the commutator relation for quantum spin operators, specifically the expression [S_i, S_j] = i ε_{ijk} S_k, using the orthonormality of the states |+\rangle and |-\rangle. The operators S_x, S_y, and S_z are defined in terms of these states.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to demonstrate the commutation relation but expresses confusion regarding the commutation of S_x and S_y, suggesting a contradiction in their calculations.
  • Some participants question the original poster's assertion that S_x and S_y commute, prompting a review of the calculations involved.
  • Others provide clarifications regarding the definitions of the operators, indicating potential typographical errors in the original post.

Discussion Status

Contextual Notes

There are indications of possible typographical errors in the definitions of the spin operators, which may be contributing to the confusion in the calculations. Participants are encouraged to verify their expressions and the use of parentheses in their calculations.

jdstokes
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Homework Statement



Using the orthonormality of [itex]|+\rangle[/itex] and [itex]|-\rangle[/itex], prove

[itex][S_i,S_j]= i \varepsilon_{ijk}S_k[/itex]

where
[itex]S_x = \frac{\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + |[/itex]
[itex]S_y = -\frac{i\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + |[/itex]
[itex]S_z = \frac{\hbar}{2}|+\rangle \langle + | - | - \rangle \langle - |[/itex]


The Attempt at a Solution



Since S_x and S_y commute, their commutator should be zero which contradicts [itex][S_x,S_y]= i S_z[/itex]. What am I missing here?
 
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S_x and S_y does not commute, check again.

If you are unsure, please write the procedure you did to get that S_x and S_y commutes.
 
Umm, is this not right?

[itex][S_x,S_y] = \frac{\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + |\left(-\frac{i\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + | \right)<br /> <br /> -\left(-\frac{i\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + | \right)\frac{\hbar}{2}|+\rangle \langle - | + | - \rangle \langle + | = 0[/itex]?
 
Is this a typo or what?
 
jdstokes said:
Is this a typo or what?

Must be; the way it's written,

[tex]S_y = -iS_x.[/tex]
 
jdstokes You must use paranthesis more carefully!

According to my copy of Sakurai:

[itex]S_y = \frac{i\hbar}{2}(-|+\rangle \langle - | + | - \rangle \langle + |)[/itex]
 
OMG why do I miss these obvious things!

Thanks for your patience malawi_glenn and George.
 
If you guys have a spare moment, would you please have a look at my new post in the quantum physics forum?
 

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