How to Prove This Quantum Mechanics Integral?

  • Thread starter Thread starter perishingtardi
  • Start date Start date
  • Tags Tags
    Integral
Click For Summary
SUMMARY

The integral \(\int_{-\infty}^\infty \frac{\sin^2 (pa/\hbar)}{p^2} \, dp\) is proven to equal \(\frac{\pi a}{\hbar}\) through the substitution \(u = \frac{pa}{\hbar}\). This transformation simplifies the problem to showing that \(\int_{-\infty}^{\infty} \frac{\sin^2 u}{u^2}\,du = \pi\). Utilizing the cosine double angle formula and integration by parts allows for further reduction to integrals involving \(\frac{\sin x}{x}\), ultimately confirming the integral's value as \(\pi\) for any \(\omega > 0\).

PREREQUISITES
  • Understanding of integral calculus, specifically improper integrals
  • Familiarity with trigonometric identities, particularly the cosine double angle formula
  • Knowledge of integration techniques, including integration by parts
  • Basic concepts of quantum mechanics and the significance of the Planck constant (\(\hbar\))
NEXT STEPS
  • Study the properties of the sinc function and its integral, \(\int_{-\infty}^\infty \frac{\sin x}{x} \, dx\)
  • Learn advanced techniques in integration, focusing on integration by parts and substitutions
  • Explore the applications of Fourier transforms in quantum mechanics
  • Investigate various proofs of the integral \(\int_{-\infty}^\infty \frac{\sin(ωx)}{x} \, dx = \pi\)
USEFUL FOR

Mathematicians, physicists, and students studying quantum mechanics or advanced calculus who are looking to deepen their understanding of integral calculus and its applications in physics.

perishingtardi
Messages
21
Reaction score
1
Mod note: Moved from the math technical sections.
I need to show that
\int_{-\infty}^\infty \frac{\sin^2 (pa/\hbar)}{p^2} \, dp = \frac{\pi a}{\hbar}.
I haven't got a clue how to integrate this function! Any help would be much appreciated thanks.
 
Last edited by a moderator:
Physics news on Phys.org
I've found through the transformation u=pa/\hbar that it is equivalent to showing
\int_{-\infty}^{\infty} \frac{\sin^2 u}{u^2}\,du = \pi, if that helps anyone.
 
You've got your substitution and your integral.

All you have to do is figure out p and dp in terms of u and du.

The algebra is really simple.
 
SteamKing said:
You've got your substitution and your integral.

All you have to do is figure out p and dp in terms of u and du.

The algebra is really simple.

Yeah I did that substitution myself to make it easier... now how do I show that the integral is equal to pi??
 
Using the cosine of double angle formula, and then integration by parts, this can be reduced to integrals of $$ \frac {\sin x} {x} $$
 
  • Like
Likes   Reactions: 1 person
Under a change of variable x = pa/h:

\frac{\hbar}{a}\int_{-\infty}^\infty \frac{sin^2 x}{x^2}dx

As suggested you can apply integration by parts and then sine double angle rule to obtain

\frac{\hbar}{a}\int_{-\infty}^\infty \frac{sin(2x)}{x}dx

The integral below has many different proofs, few of them are here
\int_{-\infty}^\infty \frac{sin(ωx)}{x}dx=\pi for any ω > 0.
 
OFF-TOPIC:

Can someone tell me what is the difference between a question asked here and a question asked on the homework forums?

This is an honest question. For example, shouldn't this question ("Difficult integral") be in the homework section?

Sorry for the off topic perishingtardi
 
Crake,
You are correct. As the sticky says at the top of this forum section, "This forum is not for homework or any textbook-style questions."

I am moving this thread to the Homework section.
 

Similar threads

Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 47 ·
2
Replies
47
Views
4K