How to read a curve level accurately

  • Thread starter Thread starter Stress D.
  • Start date Start date
  • Tags Tags
    Curve
AI Thread Summary
To read a curve level accurately in a calibrated tube, it is essential to observe the meniscus, which is the curved surface of the liquid. The correct reading should be taken at the bottom of the meniscus at eye level to avoid parallax errors. In the chemistry homework example, the final and initial volumes of hydrochloric acid are provided, allowing for the calculation of the volume used. Additionally, the discussion shifts to a related question about calculating the value of x in a hydrated compound formula, emphasizing the need for more information to solve it accurately. Accurate readings and calculations are crucial for successful chemistry experiments.
Stress D.
Messages
4
Reaction score
0

Homework Statement


i got this in chemistry homework and have never done it before...

______________________________________________________________

______________________Experiment 1___Experiment 2___Experiment 3

Final volume of
hydrochloric acid/cm(3) 48.25 44.30 46.05
_______________________________________________________________

Initial volume of
hydrochloric acid/cm(3) 18.30 14.25 16.05
_______________________________________________________________

Volume of hydrochloric
acid used/cm(3) 29.95 30.05 30.00
_______________________________________________________________


Draw a diagram to show the meniscus at the top of a column of hydrochloric acid in a caliberated tube. Explain how to read the level of the acid accurately.
 
Physics news on Phys.org
tank u very much borek...am not 2 b annoyin but i have another question hear i just got to and don't no d answer to...

Calculate the value of x in the formula Al2(SO4)3.K[2]SO4.xH2O.
 
Please use plain English, you don't want to me to waste time eciphering what you mean, don't you?

You need some more information to calculate x, at the moment (just looking at the formula) it can't be done.

--
 
I am sorry i forgot about the chatting slang...

oh and i missed out this part to the question here is the whole question

Al2(SO4)3.K2SO4.xH2O -------------> Al2(SO4)3.K2SO4 + xH2O
Hydrated Anhydrous
compound compound

When 9.48g of the hydrated compound was heated at 200 degrees celcius.
5.16g of the anhydrous compound was formed.

Calculate the value of x in the formula Al2(SO4)3.K2SO4.xH2O
 
What is formula of anhydrous salt?

What is its molar mass?

How many moles of water were lost during heating?

--
methods
 
it did not give all of that information what i typed was the most info it gave...
i had to work out its relative mass = 516g
and that the reaction occurs at 200 degrees celcius and that is it
 
If I understand correctly - 516g is a molar mass of hydrated salt?

Try to follow questions I have posted earlier.

--
 
Back
Top