How to rearrange this trig function?

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To rearrange the function y = -2sin[2π * (t + 1)/3], it can be expressed as y = -2sin[(2π/3)(t + 1)], which helps in identifying its properties. The period of the function is 3, with an amplitude of 2, a maximum value of 2, and a minimum value of -2. The range is defined as -2 ≤ y ≤ 2, while the domain is all real numbers. The horizontal phase shift is 1 unit to the left, and there is no vertical displacement. Clarifications are needed regarding whether the period should include a unit and the possibility of an amplitude of 0.
aisha
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How do I rearrange this where do I begin?

y= -2sin [ 2\pi * \frac {(t+1)} {3} ]

I need to state the period, amplitude, max/min, range, domain, horizontal phase shift, and vertical displacement

Im not sure how to rearrange the square brackets.
 
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I would distribute the 2\pi and then separate the terms into the form of -2\sin{(At + B)}. A and B will both be fractions, but setting it up in that way will allow you to more easily find all of the things you are looking for.

EDIT: The below method could be easier for you.
 
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aisha said:
How do I rearrange this where do I begin?

y= -2sin [ 2\pi * \frac {(t+1)} {3} ]

I need to state the period, amplitude, max/min, range, domain, horizontal phase shift, and vertical displacement

Im not sure how to rearrange the square brackets.
rearrange it like this.
y= -2sin [ \frac{2\pi}{3} *(t+1) ]
If you're still stuck, http://www.jmp.com/news/jmpercable/07_fall2000/regression.html for some help
 
the general form for a sine function is

y = a sin(bx - c) + d

what do each of these letters (a, b, c, and d) do?

what are the values of a, b, c, and d for the function you wrote down? you may need to do some distributing to get into this general form.
 
Thanks so much that is a BIG HUGE HELP :smile:
 
I needed to find the properties of this trig function this is what i got

period=3
amplitude=0
max=2
min=-2
range{y:-2<=y<=2}
domain {x:XER}
horizontal phase shift 1 unit left
no vertical shift

Are these values correct? Should period have a unit with it or is just 3 fine? What about the amplitude is 0 amplitude possible?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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