What is the domain of a trig function with y = 2sin(x)?

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Homework Help Overview

The discussion revolves around determining the domain of the trigonometric function y = 2sin(x). Participants are exploring the properties of the sine function and its transformations.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the range of the function based on the properties of sine and consider how to demonstrate that the maximum and minimum values are achieved within the specified domain. Questions arise about whether to find specific x values that yield these outputs.

Discussion Status

There is an ongoing exploration of the function's characteristics, with some participants suggesting that finding specific x values could be a valid approach. The continuity of the function is also mentioned as a factor in covering the range of outputs.

Contextual Notes

One participant notes a specific domain of -π < x ≤ π, which may be a constraint in their analysis. The periodic nature of the sine function is acknowledged, indicating that both extremes of the range are reached within the given domain.

so_gr_lo
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Homework Statement
I am supposed to find the limits of a trig function, which I have managed to do, but I don’t know how to show that the range can be achieved within the given domain.
Relevant Equations
y = 2sin(x)
y = 2sin(x)

-1≤ sin(x) ≤ 1

-2 ≤ 2sin(x) ≤ 2

so -2 and 2 are the max/min limits

but the domain is -π < x ≤ π

Do I find the values of x that outputs -2 and 2 and show that they are within the domain ?
 
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2sin x has period ##2\pi## so both the minimum and the maximum value are realized in the domain. Draw the graph.
 
so_gr_lo said:
Do I find the values of x that outputs -2 and 2 and show that they are within the domain ?
That is a good approach. Then use the continuity of the function to say that it covers everything in between.
 
yeah I think that might be what is expected, thanks
 

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