How to show light from laser pointer is plane polarised?

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SUMMARY

The discussion centers on demonstrating that light from a laser pointer is plane polarized by passing it through a polarizing filter and observing changes in intensity as the filter is rotated. It is established that unpolarized light will maintain a constant transmitted intensity of half the incident intensity regardless of the filter's angle, while plane polarized light will exhibit maximum intensity at certain angles and zero at others. The conversation clarifies that plane polarized light can be fully or partially polarized, with the transmitted intensity depending on the mix of polarized and unpolarized light.

PREREQUISITES
  • Understanding of polarizing filters and their function
  • Knowledge of light polarization concepts
  • Familiarity with intensity calculations in optics
  • Basic principles of Brewster's angle
NEXT STEPS
  • Research the mathematical principles behind Malus's Law
  • Learn about Brewster's angle and its applications in optics
  • Explore the differences between fully polarized and partially polarized light
  • Investigate the behavior of light when reflected off dielectric surfaces
USEFUL FOR

Students and professionals in physics, particularly those studying optics, as well as educators looking to explain light polarization concepts effectively.

songoku
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Homework Statement
A teacher has a laser pointer. The laser pointer emits a narrow beam of plane-polarised light. Describe how the teacher can demonstrate that the light from the laser pointer is plane polarised.
Relevant Equations
Malus Law
The answer key is the light is directed through one polarising filter then filter is rotated and the light changes intensity.

I don't understand how that proves that the light is plane polarised. I think if the light is unpolarised, the intensity will also change when it passes through polarising filter so how can we tell the difference between unpolarised and plane polarised light?

Also, by "plane polarised", does it mean fully polarised or partially polarised or can be both?

Thanks
 
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songoku said:
The answer key is the light is directed through one polarising filter then filter is rotated and the light changes intensity.

I don't understand how that proves that the light is plane polarised. I think if the light is unpolarised, the intensity will also change when it passes through polarising filter
If unpolarised, the transmitted intensity won't change as the angle changes. The transmitted intensity will remain constant – it will be half of the incident intensity, whatever the angle is.

Suppose the incident intensity is I and you change the angle. What can you say about the maximum and minimum transmitted intensities when:
a) the incident light is fully plane polarised?
b) the incident light is partially plane polarised?
 
Although I have not tried it, I suppose one could bounce the beam off a dielectric surface at Brewster's angle, rotate the laser and watch the reflected intensity. No analyzer needed.
 
Steve4Physics said:
If unpolarised, the transmitted intensity won't change as the angle changes. The transmitted intensity will remain constant – it will be half of the incident intensity, whatever the angle is.
Ah ok, now I understand. I misinterpreted the answer.

Steve4Physics said:
Suppose the incident intensity is I and you change the angle. What can you say about the maximum and minimum transmitted intensities when:
a) the incident light is fully plane polarised?
b) the incident light is partially plane polarised?
a) the maximum will be I and the minimum will be zero

b) sorry I don't know for this one

Thanks
 
songoku said:
a) the maximum will be I and the minimum will be zero.
Yes.

songoku said:
b) sorry I don't know for this one
Sorry, I should have been clearer. It depends on the 'mix'. Suppose the intensities of the polarised and unpolarised incident light are U and P respectively. The total incident intensity is I = U+P.

Half the unpolarised always gets through. Between 0 and P of the polarised light gets through. The min. and max. transmitted intesities are therefore U/2 and P + U/2.
 
Thank you very much for the help and explanation Steve4Physics and kuruman
 
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