How to Simplify an Expression with Invertible Matrices?

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Homework Help Overview

The discussion revolves around simplifying an expression involving invertible matrices A, B, and A-B, specifically the expression (A - B)^{-1}A(A^{-1} - B^{-1})B.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the simplification of the expression and question the correctness of the final steps in the original poster's attempt. There is a focus on the properties of invertible matrices and the implications of matrix inverses.

Discussion Status

Some participants provide feedback on the original poster's simplification, indicating that the last step may not be correct. There is an ongoing exploration of the relationship between the matrices involved, with suggestions to reconsider the definitions and assumptions made in the simplification process.

Contextual Notes

Participants note the importance of correctly identifying the relationships between the matrices A, B, and their inverses, particularly in the context of the expression (A - B)^{-1} versus (B - A)^{-1>.

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Homework Statement


For the invertible matrices A, B and A-B, simplify the expression [tex](A - B)^{-1}A(A^{-1} - B^{-1})B[/tex].


Homework Equations


properties of invertible matrices


The Attempt at a Solution


[tex](A - B)^{-1}A(A^{-1} - B^{-1})B[/tex]
= [tex](A - B)^{-1}(AA^{-1}B - AB^{-1}B)[/tex]
= [tex](A - B)^{-1}(IB - AI)[/tex]
= [tex](A - B)^{-1}(B - A)[/tex]
= [tex]I[/tex]

Am I correct?
 
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Almost. The last step isn't quite correct.
 
Verrrry close. Check your last step.
 
So it just ends here?

[tex](A - B)^{-1}(B - A)[/tex]
 
No, you can simplify it. Consider this. Let C=B-A. Then C-1=(B-A)-1, but in your expression, you have (A-B)-1, which isn't the same matrix.
 
vela said:
No, you can simplify it. Consider this. Let C=B-A. Then C-1=(B-A)-1, but in your expression, you have (A-B)-1, which isn't the same matrix.

Ok, so then the answer is:

[tex]-I[/tex] ?
 
:approve:
 
Thanks
 

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