How to simulate Ground bounce on AC line

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To simulate ground bounce on a 220V AC system, one approach is to use a SPDT relay to toggle between different ground connections, although this may not fully replicate real-world conditions. The discussion highlights the importance of understanding earth potential rise and the ground potential gradient around substations during faults. SPICE can be utilized to model various ground connections and their effects on circuit behavior, allowing for a more accurate simulation of ground bounce. Empirical data can be gathered using impedance measurement tools like LCR meters and VNAs to inform the simulation parameters. The potential impact of AC ground bounce on 5V DC logic circuits is acknowledged, with the likelihood of glitches being mitigated by bypass capacitors.
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I am not talking about Digital circuit ground bounce on PCB.
How do I simulate a Ground bounce for a system that runs on 220V AC.
In real field conditions, the system might be connected to different grounds. How do i replicate this in the lab.

Can I have a SPDT relay between GND1 & GND2. I can just toggle to simulate ground bounce?
 
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I'm not sure what you mean by "Ground bounce on AC line". If you are trying to simulate earth potential rise, good luck. Here's what the ground potential gradient might look around a substation due to a fault.

625px-Touch_Potential.jpg
 
With SPICE you can define "grounds" in various parts of your circuit that are not actually SPICE ground node 0. You then can tie these remote grounds to SPICE ground via transmission lines and inductances to model the physical line effects that create ground bounce. To tie this to empirical data, you use various impedance measurement equipment such as LCR meters and VNAs to estimate the parameter values for these ground components.
 
jsgruszynski,
Simulation will help. But i need to do this in real.

I think I am trying to find out if the 220VAC ground bounce has any effect on the logic circuits running at 5VDC.
If it screws up the data.
Mostly likely it will result in a glitch. But i guess the bypass caps will take care of that.
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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