- #1
Tombow2558
- 3
- 0
How can I solve this equation ?
Thanks
Thanks
Last edited:
Oh, I am sorry matt, because the titles still the same even when I edited, I also didn't see your post, okey , thanks for your answer. :)matt grime said:it is one for all rational x, and hence, if we've any intent on it being continuous it is 1 for all real x, a non-rigorous explanation admittedly but it agrees with the proper exp{xlog1} definition.
"1^x" means that 1 is raised to the power of x. This is a mathematical notation used to represent an exponential function.
Since 1 raised to any power is still 1, the solution to "1^x" is always 1.
Yes, you can use any real number for x when solving "1^x". However, the solution will always be 1.
Since the solution is always 1, there is no need for specific tips for solving "1^x". However, you can simplify the expression by canceling out the exponent, which will always result in 1.
For example, if x = 5, then "1^x" would be solved as 1^5, which equals 1. Similarly, if x = 0, then "1^x" would be solved as 1^0, which also equals 1.