How to Solve a Nonlinear ODE using Variable Changes

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SUMMARY

The discussion focuses on solving the nonlinear ordinary differential equation (ODE) given by du/dx = (u + x√(x² + u²)) / (x - u√(x² + u²)) through variable changes to x = rcos(θ) and u = rsin(θ). The user attempts to derive the equation for d(θ)/dr but encounters confusion leading to an incorrect conclusion of 1 = 0. The correct answer is d(θ)/dr = 1, highlighting the need for proper differentiation of x and u in terms of r and θ using the product rule.

PREREQUISITES
  • Understanding of nonlinear ordinary differential equations (ODEs)
  • Familiarity with variable substitution techniques in differential equations
  • Knowledge of trigonometric identities, specifically sin²(θ) + cos²(θ) = 1
  • Proficiency in applying the product rule for differentiation
NEXT STEPS
  • Study the method of variable changes in solving nonlinear ODEs
  • Learn about the product rule in calculus and its applications in differentiation
  • Explore trigonometric identities and their relevance in simplifying equations
  • Practice solving nonlinear ODEs with different variable substitutions
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Students and researchers in mathematics, particularly those focused on differential equations, as well as educators teaching advanced calculus concepts.

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Homework Statement



Solve the nonlinear ODE

du/dx=(u+x√(x^2+u^2 ))/(x-u√(x^2+u^2 ))

by changing variables to x=rcos(theta), u=rsin(theta) and converting the equation to one for d(theta)/dr.

The Attempt at a Solution



Not sure if I'm going in the right direction.

du/dx = du/d(theta) x d(theta)/dx

u = rsin(theta), du/d(theta) = rcos(theta)
x = rcos(theta), dx/d(theta) = -rsin(theta),
i.e. d(theta)/dx = -1/rsin(theta)

so du/dx = rcos(theta)/-1rsin(theta) = - cos(theta)/sin(theta)

then i sub x=rcos(theta), u=rsin(theta) in the main equation

- cos(theta)/sin(theta) = rsin(theta)+rcos(theta)√(r^2sin^2(theta) etc etc..

so i gather the r^2, and make the sin^2+cos^2 both to one, then the √r^2 goes to just 'r'.

then i take divide the whole equation by r

du/dx = -cos(theta)/sin(theta) = [sin(theta)+rcos(theta)]/[rcos(theta)-rsin(theta)

so i times the sin(theta) over the right side and the other to the right..
and i get 1=0...

can someone put me in the right direction on what i did wrong?

thankyou.
 
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actually the answer is d(theta)/dr = 1, if any of you were wondering.

needed to differentiate x and u in terms of r and theta with the product rule.
 

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