How to solve a related rates problem with an expanding square?

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carlodelmundo
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Homework Statement



When the area of an expanding square, in square units, is increasing three times as fast as its side is increasing, in linear units, the side is

a.) 2/3
b.) 3/2
c) 3
d) 2
e) 1

Homework Equations



A = s^2
dA/dt = 3s^2


The Attempt at a Solution



Can anyone give me hints on how to start this problem?
 
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Okay, Dick.

I get dA/dt = 2s dS/Dt. Since it's saying that the area is increasing three times as fast as its side is increasing... 2s must equal to 3. or s = 3/2

is this correct?
 
carlodelmundo said:
Okay, Dick.

I get dA/dt = 2s dS/Dt. Since it's saying that the area is increasing three times as fast as its side is increasing... 2s must equal to 3. or s = 3/2

is this correct?

You betcha.
 
Thank you, Sir.