How to Solve an Equation with Natural Logarithms?

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To solve the equation x + ln(6 - 2e^x) = ln(4), one can utilize the properties of logarithms and exponentials. Specifically, taking e to the power of both sides helps simplify the expression. It's important to note that there is no specific form for ln(a - b), which can complicate the process. Understanding the relationship e^(a+b) is crucial for further manipulation. The user successfully resolved their confusion with the provided guidance.
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[SOLVED] Simple algebraic equation

Homework Statement


I got stuck on solving an equation on this step...
x+ln(6-2e^x)=ln4


Homework Equations





The Attempt at a Solution



I just don't know how to do ln(6-2e^x)... in general, what's ln(a-b)?

Thanx in advance.
 
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There is no form for ln(a-b). Take e to the power of both sides of your equation. You do know a form for e^(a+b), right?
 
i got it thanks alot
 

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