How to Solve an Inequality with Greatest Integer Function and Fractional Part?

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The discussion focuses on solving the inequality x^2 ≥ [x]^2, where [x] represents the Greatest Integer Function. The approach involves manipulating the inequality to express it as (x + [x])(x - [x]) ≥ 0, leading to conditions on x. Key insights include the realization that x must lie within the intervals (-∞, -[x]] and [x, ∞). Participants seek clarification on the steps taken to arrive at these conclusions, indicating some confusion in the initial reasoning. The discussion ultimately emphasizes the importance of correctly interpreting the properties of the Greatest Integer Function and the fractional part.
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Homework Statement


x^2 \geq [x]^2

[] denotes Greatest Integer Function
{} denotes Fractional Part

Homework Equations



The Attempt at a Solution



x^2-[x]^2 \geq 0 \\<br /> (x+[x])(x-[x]) \geq 0 \\<br /> -[x] \leq x \leq [x] \\<br />
Considering left inequality
<br /> x \geq -[x] \\<br /> \left\{x\right\} \geq -2[x]<br />
 
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utkarshakash said:

Homework Statement


x^2 \geq [x]^2

[] denotes Greatest Integer Function
{} denotes Fractional Part

Homework Equations



The Attempt at a Solution



x^2-[x]^2 \geq 0 \\<br /> (x+[x])(x-[x]) \geq 0
How do you go from the above step to the next step.

(It does look valid, but an explanation seems to be in order.)

-[x] \leq x \leq [x] \\<br />
Considering left inequality
<br /> x \geq -[x] \\<br /> \left\{x\right\} \geq -2[x]<br />
 
SammyS said:
How do you go from the above step to the next step.

(It does look valid, but an explanation seems to be in order.)

Ah! I made a silly mistake there. Actually it should be like this

x \in \left( -∞, -[x] \right] U \left[ [x],∞ \right)
 
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