How to solve this integration problem problem did but got wrong answer

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SUMMARY

The discussion focuses on solving a volume integration problem using the cylindrical shells method for the curves defined by the equations x=1+(y-2)^2 and x=2. The user initially calculated the integral as 142.42 but realized the error stemmed from not correctly subtracting the curve x=2 from x=1+(y-2)^2. The correct setup for the shell length is essential for accurate volume calculation, leading to the correct integration limits of 1 and 3.

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Homework Statement


Find the volume generated by rotating the region bound by the given curves about the x axis



Homework Equations


x=1+(y-2)^2, x=2

The Attempt at a Solution



i solved the problem using cylinder shells method. the solution equation i got was
integration of 2phiy(1+y^2-2y+4)dy. the upper limit of the equation i got was 3 and the lower limit was 1.
the answer i got was 142.42 but it came out to be wrong.
can anyone help me.
 
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The length of your shell should be 2-(1+(y-2)^2), right? When I expand that, I don't get (1+y^2-2y+4). Can you check that part?
 
thank you i got it now...what i did in my solution was that i didnt subtracted x=2 from the equation x= 1+ (y-2)^2.
thanks for the help.
 

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