How to use clairaut's theorem with 3rd order partial derivatives

Click For Summary
To apply Clairaut's Theorem for third-order partial derivatives, it is essential to establish that the mixed partial derivatives are continuous. The theorem states that if the second-order mixed derivatives are continuous, then the order of differentiation does not affect the result, leading to the equality fxxy = fyxy = fyyz. An attempt to differentiate the second partial derivatives was made, but it was unsuccessful, prompting a counterexample using the function f = (x^3)(y^2)(z). The specific values (5, 7, 11) were suggested for testing the function's behavior. Understanding the continuity of these derivatives is crucial for applying Clairaut's Theorem effectively.
physicsidiot1
Messages
5
Reaction score
0

Homework Statement



Use Clairaut's Theorem to show that is the third order partial derivatives are continuous, then fxxy=fyxy=fyyz

Clairaut's Theorem being: fxy(a,b)=fyx(a.b)

Homework Equations



fxyy=d/dy(d2f/dydx)=d^3f/dy^2dx

The Attempt at a Solution



Tried to differentiate the second partial derivatives but it didn't work out.
 
Physics news on Phys.org
counter example

Try when f = (x^3)(y^2)(z). After differentiating, try (5,7,11).
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
5
Views
4K
  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K