How to use the Heaviside step function to solve these equations

[slider527]

Heaviside? HELP

hey there peeps,

could u guys help me out with heaviside step function..cu zi don't understand anything bout how it works and how to apply to a particular problem...

could u guys explain in detail how to solve the next equations using heaviside:
exp[-2s]
F(s)= --------
s^2+s-2
and
__
|
| 0 for t<2
f(t) <
| t^2-2t+2 for t (greater or equal to ) 2
|__


ThnQ ...it means a lot to me

 

[fannemel]

The heaviside function is most easily explained as a on-switch.

$$h(u) = \left\{ \begin{array}{rcl}<br /> \ 0 & \mbox{for} & t < u\right \\ 1 & \mbox{for} & t \geqq u<br /> \end{array}\right$$

Thus if you multiply a function with the Heaviside function, the output are zero until the t = u, from that point, the function is similar to what it would look like without multiplying with Heaviside.

I didn't understand your notation so didn't get the equation, was it laplace?

 

[slider527]

The heaviside function is most easily explained as a on-switch.

$$h(u) = \left\{ \begin{array}{rcl}<br /> \ 0 & \mbox{for} & t < u\right \\ 1 & \mbox{for} & t \geqq u<br /> \end{array}\right$$

Thus if you multiply a function with the Heaviside function, the output are zero until the t = u, from that point, the function is similar to what it would look like without multiplying with Heaviside.

I didn't understand your notation so didn't get the equation, was it laplace?

well Laplace transformations are used to solve differential equations...
thnqs anyway,...mayb i can figure out woth u just said

 

[PerennialII]

could u guys explain in detail how to solve the next equations using heaviside:
exp[-2s]
F(s)= --------
s^2+s-2
and
__
|
| 0 for t<2
f(t) <
| t^2-2t+2 for t (greater or equal to ) 2
|__

I was kind of left somewhat puzzled what actually comes out of this notation ... could you clarify a bit ?