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Laplace transforms of heaviside step functions

  1. Sep 22, 2010 #1
    1. The problem statement, all variables and given/known data

    Consider the initial value problem
    y'' + 1/3y' + 4y = fk(t)

    with y(0) = y'(0) = 0,

    fk(t) = 1/2k for 4 - k < t < 4 + k
    0 otherwise

    and 0 < k < 4.

    (a) Write fk(t) in terms of Heaviside step functions and then solve the initial value problem.

    3. The attempt at a solution

    I can convert it to a heaviside function and do the laplace transform and get

    fk(t)= 1/2k H(t-(4-k)) - 1/2k H(t+(4-k))

    and then taking the laplace transform of the entire equation get

    Y(s) = 1/2k(s2+1/3 s + 4) * (e-(4-k)s/s - e-(4+k)s/s)

    Im assuming this is corrent. But then how do I take the inverse laplace transform of this???
  2. jcsd
  3. Sep 22, 2010 #2


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    Homework Helper
    Gold Member

    I think if you graph this out, you'll find it is not the function you want

    [tex]H(t-4+k)-H(t+4-k)=\left\{\begin{array}{lr}-1 &, t< 4-k \\ 1 &, t>4-k\end{array}\right.[/tex]

    Much like the other problem you posted, you'll want to use the linearity of the inverse LT:


    For each of the two individual inverse LTs, you might want to use the method of partial fraction decomposition
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