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How to write taylor series in sigma notation

  1. Dec 10, 2012 #1
    1. The problem statement, all variables and given/known data
    My Calc II final is tomorrow, and although we never learned it, it's on the review.
    So I have a few examples. Some I can figure out, some I cant.

    Examples: f(x)=sinh(x), f(x)=ln(x+1) with x0=0, f(x)=sin(x) with x0=0, f(x)=1/(x-1) with x0=4
    The only one of those that I was able to figure out was sinh(x). The rest I don't get. I don't need someone to show me how to do all of them, but maybe just show me how to do these types of problems in general using one of those as an example?

    I am really just completely lost here. I could definitely use some help.
    Thank you!
    And sorry if I did something wrong in terms of posting this thread, I have never used Physics Forum before.
     
  2. jcsd
  3. Dec 10, 2012 #2

    SteamKing

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  4. Dec 10, 2012 #3

    Dick

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    I'd be interested in knowing how you got sinh(x) and couldn't get sin(x). They are really pretty similar. Are you having trouble representing the alternating sign?
     
  5. Dec 10, 2012 #4
    My bad...I actually did get sin(x)!
    Okay, maybe I should be more specific.
    f(x) = 1/(x-1), x0=4
    f'(x) = -1/((x-1)^2)
    f"(x) = 2/((x-1)^3)
    f'''(x) = -6/((x-1)^4)

    Plugging in 4:
    f(x) = 1/3
    f'(x) = -1/9
    f"(x) = 2/27
    f'''(x)=-6/81

    So the taylor series is 1/3 + -(x-4)/9 + 2(x-4)^2/54 + -6(x-4)^3/486...

    Now I just found in my notes that the format for sigma notation should be the sum from n=0 to infinity of the n-th derivative of f(a) * (x-a)^n/n!
    But I just have no idea how to take that taylor series and get it into that format.
    I think my brain is dead from doing too much math :(
     
  6. Dec 10, 2012 #5
    Okay well the answer to that last one should be (-1)^n * (x-4)^n / 3^(n+1)
    I get the (-1)^n (because the signs are alternating) and I get the (x-4)^n. But what I do not get is where the 3^(n+1) is coming from.
    Also, how do you know when do use (-1)^n and when to use (-1)^(n+1)? What's the difference?
     
  7. Dec 10, 2012 #6

    SammyS

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    (-1)n is positive for even n, negative for odd n.

    (-1)n+1 is positive for odd n, negative for even n.
     
  8. Dec 10, 2012 #7
    Ahh okay that makes sense!
    Thanks!
    Well...at least if I make an educated guess I will probably be able to get a least partial credit...
     
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