How to write this expression in terms of a Hyperbolic function?

AI Thread Summary
The equation can be expressed in terms of hyperbolic functions, specifically as Eq = e^{-ht} (e^{t\sqrt{x}} + e^{-t\sqrt{x}}) = 2 e^{-ht} cosh(t\sqrt{x}). The discussion highlights the challenge of combining two separate equations, f(t,h,x) and g(t,h,x), into a single expression, which some participants argue is incorrect. There is a clarification needed regarding the use of brackets and notation, particularly the lowercase 'c' for cosh. The participants emphasize that relating the original equation directly to cosh may not be straightforward. Overall, the conversation revolves around the proper representation of the equation in hyperbolic terms.
Safinaz
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Homework Statement
How to write this expression in terms of a Hyperbolic function
Relevant Equations
How to write :

##
Eq= e^{t ( -h \pm \sqrt{ x} )}
##

I terms of ##Cosh (x) = e^x + e^{-x} /2 ##
The eqution can be written as:

##
Eq= e^{t( -h + \sqrt{ x} )} + e^{t( -h -\sqrt{ x} )}
##

Can this be written in terms of Cosh x ?
 
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It could be written in terms of ##\cosh \sqrt x##.
 
PeroK said:
It could be written in terms of ##\cosh \sqrt x##.
So can it written as:

## Eq = e^{ -ht} ( e^{t\sqrt{x}} + e^{-t\sqrt{x}} ) = 2 e^{ -ht} Cosh ( t \sqrt{x}) ##?
 
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Safinaz said:
How to write :
##Eq= e^{t ( -h \pm \sqrt{ x} )}##
I presume that represents 2 different 'equations':
##f(t,h,x)= e^{t ( -h + \sqrt{ x} )}## and
##g(t,h,x)= e^{t ( -h - \sqrt{ x} )}##

Safinaz said:
##Cosh (x) = e^x + e^{-x} /2 ##
You are missing brackets and should use a lower case c for ##\cosh##.

Safinaz said:
The eqution can be written as:
##Eq= e^{t( -h + \sqrt{ x} )} + e^{t( -h -\sqrt{ x} )}##
Looks like you are trying to express the two differnt equations as a single equation. That sounds wrong to me. It's a bit like saying ##x = 1 \pm \sqrt 2## and then considering the value of ##(1+\sqrt 2) + (1 -\sqrt 2)## (which is ##2##). It doesn't work.
 
Safinaz said:
Can you please write the formula?
It's fairly obvious. I thought the question was to relate that to ##\cosh x##, which I don't think can be simply done.
 
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$$2e^{-ht}=\cosh{ht}-\sinh{ht}$$
 
Safinaz said:
Homework Statement: How to write this expression in terms of a Hyperbolic function
Relevant Equations: How to write :

##
Eq= e^{t ( -h \pm \sqrt{ x} )}
##

I terms of ##Cosh (x) = e^x + e^{-x} /2 ##

Is this the question as given to you, or does it represent where you got to in answering some other question? If the latter, please state the original question.
 
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