Let us suppose a rod is inclined on the ground such that its middle point is supported by a peg. It is a uniform rod and the point where it touches the ground is A, mid-point (also the centre of gravity) is C. The rod is inclined at angle theta with horizon. So, we can divide the components of weight into mgcos(theta) against the normal of the rod, andg sin (theta) along the rod. Then how do we measure it if the peg was at any other point D (I meant measure the weight at D), which is not the centre of gravity? What are the conditions to support the rod then, when the angle is same? How frictional force is at the point touching the ground?