Hwk. Problem:Gravitational Potential Energy

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SUMMARY

The discussion centers on calculating the change in gravitational potential energy (PE) for a skier using the formula ΔPE = mgh. The skier, weighing 70.0 kg, rides a lift that is 2860 m long at an angle of 14.8° with the horizontal. The angle is irrelevant for the potential energy calculation, as only the change in height is necessary. Participants clarify that the formula simplifies to ΔPE = mgΔh, emphasizing that the angle is a distraction.

PREREQUISITES
  • Understanding of gravitational potential energy concepts
  • Familiarity with the formula ΔPE = mgh
  • Basic knowledge of trigonometry, specifically sine functions
  • Ability to calculate height from lift length and angle
NEXT STEPS
  • Learn how to calculate height using trigonometric functions (e.g., h = L * sin(θ))
  • Explore the implications of gravitational potential energy in different contexts
  • Study the relationship between mass, height, and gravitational force
  • Investigate real-world applications of gravitational potential energy in sports and engineering
USEFUL FOR

Students studying physics, educators teaching energy concepts, and anyone interested in the practical applications of gravitational potential energy calculations.

shawonna23
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A 70.0 kg skier rides a 2860 m long lift to the top of a mountain. The lift makes an angle of 14.8° with the horizontal. What is the change in the skier's gravitational potential energy?

Would I use the equation: PE= (mg*final height) - (mg*initial height)? What do I do with the 14.8degrees? Please help. I'm stuck.
 
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Potential energy does not have anything to do with angles. All that matters is the change in altitude. The angle was provided specifically to confuse you.

- Warren
 
Problem: Gravitational Potential Energy

if the 14.8 degrees is useless, what would i have to do to solve the problem. I don't get it?
 
The change in gravitational potential energy when moving a mass m through a height h is just

\Delta PE = m g \Delta h

- Warren
 

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