Hybridizing Xenon: Exciting Electrons to d Orbitals?

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SUMMARY

Hybridizing xenon involves exciting two electrons from the 5p orbital to the vacant 5d orbital, resulting in four unpaired hybridized electrons: two in the 5p and two in the 5d orbitals. Despite this hybridization, d-electrons do not significantly contribute to bonding in xenon compounds. For example, in xenon tetrafluoride (XeF4), the bonding primarily utilizes the p orbitals of xenon, with multiple resonance structures illustrating the bonding nature. Hybridization does not enhance bonding capabilities in xenon, as evidenced by the resonance structures of xenon difluoride (XeF2) and xenon tetrafluoride (XeF4).

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  • Knowledge of xenon compounds and their bonding characteristics
  • Basic principles of molecular orbital theory
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Homework Statement



When we hybridize xenon, do we excite one electron each from its 5s and 5p orbitals to its d orbital?

I know the ground state xenon looks something like this:
http://i.minus.com/jbt6v4btYTThFJ.jpg

But when it's hybridized does Xenon look like this?

http://i.minus.com/jkkyRXOE2bht6.jpg
 
Last edited by a moderator:
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Of the 5s and 5p electrons in the outermost orbit of Xe, two of the 5p orbital electrons get excited to the vacant 5 d orbital resulting in 4 unpaired hybridized electrons, 2 in 5p and 2 in 5d orbitals.
 
d-electrons play no mayor role in bonding in Xenon compounds. Especially there are no spd hybrid orbitals involved in bonding.
 
But how does xenon form so many bonds such as in xeF4
 
As I am not good in drawing in this forum, let's look at XeF2 instead:
You can write two mesomeric resonance structures:
F- Xe-F <-> F-Xe F-
In the case of XeF4, there are correspondingly 6 resonance structures with two F- atoms and two covalently bonded F. The bonding involves mainly the p orbitals on Xe, I don't think that hybridizing Xe will lead to any improvement.
 

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