Hydrocyclones- Calculation steps and separation results

AI Thread Summary
Hydrocyclones can effectively separate small metal particles from a closed-loop water system, with the d_50 value indicating the particle size at which the cyclone is 50% efficient. A d_50 of 7.3 micrometers suggests that half of the particles of this size will be captured, while larger particles, such as those at 200 micrometers, can achieve efficiencies exceeding 99.8%. The effectiveness of hydrocyclones generally increases with larger particle sizes, alleviating concerns about reduced efficiency for larger particles. Understanding the calculations and efficiency diagrams in resources like "Chemical Engineering Design" is crucial for accurate application. Proper analysis ensures effective separation in various particle size scenarios.
MMImpel
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Help understanding hydrocyclones and a simple calculation using an empirical equation by Bradley
Hello,

I want to see if hydrocyclones can be used in a application, where we have small metall particles that we want to extract from a closed loop water system. I found a book "Chemical Engineering Design" written by Richardson, where there are some equations given that makes it possible to calculate the effectiveness of the hydrocyclone dependent on the hydrocyclones and the water flow properties. I have used eq (10.3)

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The following in-data are used
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This gives me a value for the d_50 = 7,3 micrometer.
Firstly; what does this actually mean, will the hydrocyclone capture 50 % of the particles of the d_50 size what about if they are larger or smaller? Is it possible to determine how effective the hydrocyclone will be if the particles for instance have a d = 200 micrometers ?

 

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MMImpel said:
Firstly; what does this actually mean, will the hydrocyclone capture 50 % of the particles of the d_50 size what about if they are larger or smaller?
If I turn the page after equation 10.3, I read: ##d_{50} =## the particle diameter for which the cyclone is 50 per cent efficient, ##\mu##m

Meaning half go over the top and the remainder over the bottom.

The diagram Fig. 10.22 just above allows you to estimate the efficiency for 200 ##\mu##m particles for a cyclone with ##d_{50} = 10 ## (that's the lowest value on the left). WIth 200 ##\mu##m the highest value on the middle axis, the estimated efficiency on the rightmost axis is way off scale, so over 99.8 %.

Read carefully, work out the example 10.2 to understand what's what.

##\ ##
 
Thank you, I came to the same conclusion but was worried that I missunderstood that the effectiveness might get lower with larger particles?
Since this is really out of my comfort-zone I felt the need to double-check.

Best regards!
 
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