Hydrodynamics: Pressure of water coming out of a glass

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Homework Help Overview

The discussion revolves around determining the pressure required for water to flow at a specific velocity (2 m/sec) from a hole in a container. The context involves applying Bernoulli's Equation and understanding the relationship between pressure, velocity, and height in fluid dynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the application of Bernoulli's Equation, discussing the conversion of potential energy to kinetic energy. There are questions about the correct notation for density and the necessity of certain variables in the calculations.

Discussion Status

The discussion is active, with participants clarifying concepts and notation related to Bernoulli's Equation. Some guidance has been provided regarding the relationship between pressure and velocity, and the relevance of the variables in the context of the problem.

Contextual Notes

Participants are navigating through the implications of the equation and the assumptions regarding the flow of water, including the need for specific variables to solve for the required pressure.

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"What pressure do you need to get water to flow at 2 m/sec coming out of a hole?"

Here is the visual of a container sitting on top of a glass of water with a hole poked through the bottom: http://i96.photobucket.com/albums/l168/synovial/fluids.jpg

Given: A1, A2, V2, (y1-y2)

Find: patm

Useful equations:
Bernoulli's Equation:
p1 +[tex]\rho[/tex] [tex]\cdot[/tex] g [tex]\cdot[/tex] y1 + 0.5 [tex]\rho[/tex][tex]\cdot[/tex] V12 = p1 +[tex]\rho[/tex] [tex]\cdot[/tex] g [tex]\cdot[/tex] y2 + 0.5 [tex]\rho[/tex][tex]\cdot[/tex] V22

A1V1 = A2V2


I'm not sure how to modify the Bernoulli's equation to combine the y1 and y2 into (y1 - y2) and to also combine the pressures into patm. Can someone please help me?
 
Last edited:
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Bernoullis is just a statement of conservation of energy.

The potential energy is the static pressure = rho*g*h where rho is density and the
kinetic energy =1/2pho*v^2.

Look familiar? So we convert from one form to the other.

Almost like a kinematics problem.
 
I'm not sure I understand. Is the pho supposed to be rho or p*rho?
 
rho throughout. But as it turns out it is a common factor leaving 2gh=v^2. As I said, does this look familiar?
 
Yes it does... especially the 2gh=v^2.

One last question: do I need the v^1, or can I find it from what is given?
 
Well if you mean v^1 is velocity, yes that is what we are trying to solve for as in equal to 2m/second. So yes you need to take the square root if that is what you are asking.
 
Yes... thank you!
 

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