Hydrostatic Force Problem - Calculus

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SUMMARY

The discussion centers on calculating the hydrostatic force on the vertical side of a tank shaped by the curves y=2x² and y=8, assuming the tank is full of water. The formula used is F=pgAd, where p is the water density (1000 kg/m³), g is gravity (9.8 m/s²), A is the area, and d is the depth. The integral set up for the calculation is ∫(1000)(9.8)(8-2x²)(2x)dx, evaluated from 0 to 2, with the final result being 313600 N. The user expresses uncertainty about the correctness of their calculations and seeks assistance.

PREREQUISITES
  • Understanding of hydrostatic pressure principles
  • Knowledge of calculus, specifically integration techniques
  • Familiarity with the concept of definite integrals
  • Basic understanding of the physical properties of water
NEXT STEPS
  • Review the derivation of the hydrostatic force formula F=pgAd
  • Study integration techniques for calculating areas under curves
  • Learn about the application of definite integrals in physics problems
  • Explore examples of hydrostatic force calculations in various tank shapes
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Students studying calculus, physics enthusiasts, and anyone involved in engineering or fluid mechanics who needs to understand hydrostatic force calculations.

HanRam
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Homework Statement


Find hydrostatic force on the vertical side of the tank that has the shape of the region bounded by the curves y=2x2, y=8. Assume that the tank is full of water.

Homework Equations


F=pgAd (force = density*gravity*area*depth)

The Attempt at a Solution


I know I need to set up and evaluate an integral, and I believe it must be evaluated from 0 to 8, since the top of the tank is at y=8. Other than this though, I have been unable to set up the integral that I need. Any help as to how the integral would be set up would be appreciated.
 
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After hours working at this problem, I think I may have figured it out, but I'm not at all sure that I did it correctly. Anyway, here is what I came up with.

\int(1000)(9.8)(8-2x^2)(2x)dx

After calculating this integral from 0 to 2 (I did this because x=0 corresponds to the bottom, and x=2 corresponds to the top), I multiplied my result by 2 to compensate for the fact that I was only integrating for the right side (0 to 2), and by multiplying by 2, that would cover the left side (-2 to 0).

My final result was 313600 N. Can anybody tell me if I went wrong somewhere? (Which I have a feeling I did).
 
You know anything about calculating hydrostatic force? Wanna help me calculate hydrostatic force here? No? I could use a little help. I need a little assistance. I never took a calculus class, and I need a little help. Ok, I'm just coming flat out and saying 'help me'. Anybody want to help a semi-retarded individual calculate hydrostatic force? 25, 30 dollars. 30 dollars to calculate hydrostatic force. 35 dollars to calculate hydrostatic force right now.

I'll give you 10 dollars for a typed response. 10 dollars. Anybody want to make 10 dollars and respond virtually? No?
 

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