Hyperbolic, Parabolic or Elliptical Orbit?

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SUMMARY

The discussion centers on the classification of a comet's orbit based on its initial distance from the Sun (d AUs) and its speed relative to Earth's speed (q). It is established that if q²·d is greater than, equal to, or less than 2, the orbit will be hyperbolic, parabolic, or elliptical, respectively. The specific energy formula, given by (v²/2) - (μsun/r) = ε, indicates that an object will orbit the Sun if its specific energy (ε) is less than 0, follow a parabola if ε equals 0, and follow a hyperbola if ε is greater than 1. The heliocentric gravitational constant (μsun = 1.327124421 × 1011 km3/sec2) is crucial for these calculations.

PREREQUISITES
  • Understanding of orbital mechanics and celestial dynamics
  • Familiarity with the concepts of eccentricity in conic sections
  • Knowledge of gravitational constants, specifically the heliocentric gravitational constant
  • Basic proficiency in algebra and physics equations
NEXT STEPS
  • Study the derivation of the specific energy formula in orbital mechanics
  • Learn about the implications of eccentricity in different types of orbits
  • Explore the applications of the heliocentric gravitational constant in celestial navigation
  • Investigate the differences between hyperbolic, parabolic, and elliptical trajectories in astrodynamics
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Astronomers, astrophysicists, and students of physics who are interested in understanding the dynamics of cometary orbits and the mathematical principles governing celestial motion.

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A comet is first seen at a distance of d AUs from the Sun and is traveling with a speed of q times the Earth's speed.

Apparently it can be shown that if q2·d is greater than, equal to, or less than 2, then the comet's orbit will be hyperbolic, parabolic or elliptical respectively.

Any idea how this can be shown??

I know that, in general, ε (eccentricity) is less than, equal to, or greater than 1 for an ellipse, parabola, and hyperbola respectively.
 
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Yes, see post: https://www.physicsforums.com/showthread.php?t=40525

Just substitute the heliocentric gravitational constant for the geocentric gravitational constant.

The specific energy of object (energy per unit of mass) is just:

\frac{v^2}{2}-\frac{\mu_{sun}}{r}=\varepsilon
where v is velocity, r is position and \mu_{sun}=1.327124421\times 10^{11}km^3/sec^2

If the specific energy is less than 0, the object will orbit the Sun. If equal to 0, the object will follow a parabola. If greater than 1, the object will follow a hyperbola.

'e' is normally used to represent eccentricity (depends on the book you're using)
 

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