I am having trouble with a Capacitor problem I can't find the find formula for.

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SUMMARY

The discussion centers on calculating the charge on a capacitor with given parameters: a separation distance of 1mm, an electric field of 100 N/C, and a capacitance of 5 µF. The relevant equation for this calculation is Q = CV, where Q is the charge, C is the capacitance, and V is the voltage. To find the voltage, the electric field must be converted to volts per meter (V/m), allowing for the determination of charge using the capacitance value.

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Homework Statement



The two metal plates of a capacitor are separated by a distance of 1mm. The electric field between the two plates is measured to be 100 N/C. If the capacitance is measured to be 5 uF, what is the magnitude of the charge on each plate, in Coulombs?

Homework Equations


That's my problem as I can't find the appropriate equation.


The Attempt at a Solution


Spent hours searching for the equation and now I'm too frustrated to continue.
 
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jjj0922 said:

Homework Statement



The two metal plates of a capacitor are separated by a distance of 1mm. The electric field between the two plates is measured to be 100 N/C. If the capacitance is measured to be 5 uF, what is the magnitude of the charge on each plate, in Coulombs?

Homework Equations


That's my problem as I can't find the appropriate equation.


The Attempt at a Solution


Spent hours searching for the equation and now I'm too frustrated to continue.

Welcome to the PF.

Well, what equations do you have that are related to capacitance? I'm at home and my EE books are at work, but it seems that you don't know the area of the cap so you can't work with the Q=CV equation directly at first. Can you convert that electric field into V/m units instead? That would give you the cap voltage, and knowing the measured capacitance would give you the Q value...
 

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