I don't understand why velocity is positive here?

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SUMMARY

The discussion centers on calculating the average velocity of a horse that gallops 116 meters away from its trainer in 14.0 seconds and then returns halfway in 4.8 seconds. The correct formula for average velocity is established as displacement divided by time elapsed, where displacement is defined as xf - xi. The confusion arose from misidentifying the initial position (xi) as 116 meters instead of zero, leading to the correct calculation of average velocity as (116 - 58) / 18.8 seconds.

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Homework Statement



It says that a horse gallops 116m away from its trainer in 14.0s and then abruptly turns and gallops halfway back in 4.8s.

I need to calculate average velocity . displacement/ time elapsed. displacement is xf-xi.

Homework Equations


avg velocity= displacement/ time elapsed

displacement = xf-xi

The Attempt at a Solution


Shouldn't it be (58-116)/18.8? the solutions manual says its 116-58/18.8...why?
 
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Frankenstein19 said:

Homework Statement



It says that a horse gallops 116m away from its trainer in 14.0s and then abruptly turns and gallops halfway back in 4.8s.

I need to calculate average velocity . displacement/ time elapsed. displacement is xf-xi.

Homework Equations


avg velocity= displacement/ time elapsed

displacement = xf-xi

The Attempt at a Solution


Shouldn't it be (58-116)/18.8? the solutions manual says its 116-58/18.8...why?

Nevermind, it's a dumb question I got it. xi does not equal to 116, it's equal to zero.
 

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