I hate signs, a simple problem with electric potential

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SUMMARY

The discussion focuses on calculating the speed of a proton and an electron accelerated through an electric potential difference of 120V. The key equation used is ΔPE = qΔV = -ΔKE, which leads to the relationship qΔV = -1/2 mv². The confusion arises from the direction of the electric field and potential difference; a proton accelerates from higher to lower potential, while an electron accelerates from lower to higher potential, necessitating a reversal of the field direction for the electron.

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flyingpig
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Homework Statement



(a) Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 120V

(b) Calculate the speed of an electron that is accelerated from rest through an electric potential difference of 120V




The Attempt at a Solution



Basically it is

\Delta PE = q\Delta V = -\Delta KE

q\Delta V = -\frac{1}{2}mv^2

So what is the problem? It works fine with an electron sign the signs cancel out, but not the electron. Why?
 
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flyingpig said:

Homework Statement



(a) Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 120V

(b) Calculate the speed of an electron that is accelerated from rest through an electric potential difference of 120V




The Attempt at a Solution



Basically it is

\Delta PE = q\Delta V = -\Delta KE

q\Delta V = -\frac{1}{2}mv^2

So what is the problem? It works fine with an electron sign the signs cancel out, but not the electron. Why?
You have to reverse the field to accelerate the electron. So the \Delta V has to change direction.

The convention is to assign to the electric field a direction which is the direction in which a positive charge will move (ie. the direction of the force on a positive charge). So the proton will accelerate from higher to lower potential (eg. from +V to 0). The electron, however, is accelerated from lower potential to higher potential (eg. from 0 to + V).

AM
 
flyingpig said:
...

So what is the problem? It works fine with an electron sign the signs cancel out, but not the electron. Why?
So what is the problem? It works fine with an electron sign the signs cancel out, but not the electron. Why?
Read what you wrote!

Are you saying it works for an electron or are you saying it doesn't work for an electron?
 
Last edited:
*but not the proton
 
SammyS said:
Read what you wrote!

Are you saying it works for an electron or are you saying it doesn't work for an electron?

flyingpig said:
*but not the proton
Huh ??

To be fair, I know what you mean, but
... it appears that you didn't even take the time to recognize that my question required MORE than an implicit yes or no.​

I suppose you meant that:
"I (the flyingpig) can get this to work for an electron, but not for a proton."

At any rate, Andrew Mason gave you enough to resolve the problem.
 

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