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flyingpig
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Homework Statement
(a) Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 120V
(b) Calculate the speed of an electron that is accelerated from rest through an electric potential difference of 120V
The Attempt at a Solution
Basically it is
[tex]\Delta PE = q\Delta V = -\Delta KE[/tex]
[tex]q\Delta V = -\frac{1}{2}mv^2[/tex]
So what is the problem? It works fine with an electron sign the signs cancel out, but not the electron. Why?