I hate signs, a simple problem with electric potential

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Homework Help Overview

The discussion revolves around calculating the speeds of a proton and an electron when accelerated through a specified electric potential difference of 120V. Participants are exploring the implications of charge signs and electric potential in this context.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to apply the relationship between electric potential energy and kinetic energy, questioning how the signs of the charges affect the calculations for protons and electrons. There is confusion regarding the direction of the electric field and how it influences the potential difference for each particle.

Discussion Status

The conversation is ongoing, with participants clarifying the roles of charge signs and electric fields in the problem. Some guidance has been provided regarding the direction of potential changes for protons versus electrons, but there is still uncertainty and a lack of consensus on the interpretation of the results.

Contextual Notes

Participants are grappling with the conventions of electric potential and the implications of charge polarity in their calculations. There is a noted need for clarity on how these conventions apply differently to protons and electrons.

flyingpig
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Homework Statement



(a) Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 120V

(b) Calculate the speed of an electron that is accelerated from rest through an electric potential difference of 120V




The Attempt at a Solution



Basically it is

[tex]\Delta PE = q\Delta V = -\Delta KE[/tex]

[tex]q\Delta V = -\frac{1}{2}mv^2[/tex]

So what is the problem? It works fine with an electron sign the signs cancel out, but not the electron. Why?
 
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flyingpig said:

Homework Statement



(a) Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 120V

(b) Calculate the speed of an electron that is accelerated from rest through an electric potential difference of 120V




The Attempt at a Solution



Basically it is

[tex]\Delta PE = q\Delta V = -\Delta KE[/tex]

[tex]q\Delta V = -\frac{1}{2}mv^2[/tex]

So what is the problem? It works fine with an electron sign the signs cancel out, but not the electron. Why?
You have to reverse the field to accelerate the electron. So the [itex]\Delta V[/itex] has to change direction.

The convention is to assign to the electric field a direction which is the direction in which a positive charge will move (ie. the direction of the force on a positive charge). So the proton will accelerate from higher to lower potential (eg. from +V to 0). The electron, however, is accelerated from lower potential to higher potential (eg. from 0 to + V).

AM
 
flyingpig said:
...

So what is the problem? It works fine with an electron sign the signs cancel out, but not the electron. Why?
So what is the problem? It works fine with an electron sign the signs cancel out, but not the electron. Why?
Read what you wrote!

Are you saying it works for an electron or are you saying it doesn't work for an electron?
 
Last edited:
*but not the proton
 
SammyS said:
Read what you wrote!

Are you saying it works for an electron or are you saying it doesn't work for an electron?

flyingpig said:
*but not the proton
Huh ??

To be fair, I know what you mean, but
... it appears that you didn't even take the time to recognize that my question required MORE than an implicit yes or no.​

I suppose you meant that:
"I (the flyingpig) can get this to work for an electron, but not for a proton."

At any rate, Andrew Mason gave you enough to resolve the problem.
 

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