I have a problem with some capacitors connected

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Discussion Overview

The discussion revolves around the behavior of two identical capacitors connected in series, with one capacitor submerged in oil. Participants explore the implications of this setup on charge distribution and energy variation, as well as the effects of the oil on the capacitors' properties.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions how charge can change between two capacitors that initially have the same charge when connected in series.
  • Another participant inquires about the effects of oil on the capacitor, suggesting it may alter the capacitor's capacity.
  • It is proposed that oil, acting as a dielectric with higher permittivity than air, will increase the capacitor's capacity.
  • Some participants argue that the change in capacity is relevant to understanding the charge dynamics between the capacitors.
  • Concerns are raised about the energy expended in the system and the role of resistance in the connecting wires or supply affecting the energy situation.

Areas of Agreement / Disagreement

Participants express differing views on the relevance of the oil's effect on capacity to the original question about charge distribution. There is no consensus on the implications of these changes for the charge dynamics between the capacitors.

Contextual Notes

Participants acknowledge that the initial charge on a capacitor remains unchanged without an external path, but the introduction of oil complicates the scenario due to changes in capacity and potential voltage variations.

anachin6000
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I've found a problem about 2 identic capacitors which have the same voltage. One of them is sinked in oil and after that the 2 capacitors are connected in series. The problem ask for the for the energy variation. I've done the problem but I don't understand something:

When the capacitors are conected they must change charge between them because of the voltage difference. They alredy had the same charges and I know that two capacitors connected in series will have the same charge. So how is possible to change charge between them?
 
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What effect might the oil have on the capacitor?
 
skeptic2 said:
What effect might the oil have on the capacitor?

It fills the space between the capacitor's plates and change it's capacity, so as a result it's voltage will be changed.
 
Why will the oil change the capacitor's capacity and will it increase or decrease it?
 
skeptic2 said:
Why will the oil change the capacitor's capacity and will it increase or decrease it?

The oil is conssidered a dielectic that have the permitivity bigger than the air so the capacity will increase.

But it's not relevant to know that for my question. I just want to know what happens with the charge.
 
anachin6000 said:
The oil is conssidered a dielectic that have the permitivity bigger than the air so the capacity will increase.

But it's not relevant to know that for my question. I just want to know what happens with the charge.
If there is no external path leading from one end of a capacitor to its other end, then initial charge on its plates remains unchanged.
 
NascentOxygen said:
If there is no external path leading from one end of a capacitor to its other end, then initial charge on its plates remains unchanged.

When I said about charge Iwas referring to the topic question not to that capacitor.
 
anachin6000 said:
The oil is conssidered a dielectic that have the permitivity bigger than the air so the capacity will increase.

But it's not relevant to know that for my question. I just want to know what happens with the charge.

It is totally relevant to your original question.
Adding oil to one of the capacitors is changing its Capacity. When you do this and the capacitors are connected in parallel, the charges will no longer be equal (Q=CV) so the voltage will change (if disconnected from the supply) or some balancing current will flow if they are connected to a supply.

There is an extra factor that you need to consider and that is the energy expended in either case. There has to be a finite resistance in connecting wires or in the supply and you get a discrepancy in the before and after energy situation. This will be resolved if you allow the energy to be dissipated in the resistances.
 
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