I have problems with integrating this

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The discussion revolves around the integration of the function \(\int_{0}^{x}\frac{1}{\sqrt{a^2 - b/x}}dx\). The user attempted substitution methods, specifically using \(u = 1/x\), but encountered difficulties. A suggested transformation involves letting \(u = a^2x - b\) and deriving the integral in terms of \(u\), leading to a more manageable form. The final expression is clarified as \(\frac{1}{a^3}\sqrt{\frac{u+b}{u}}\).

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mitochondria
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I have problems with integrating this... :(

[tex] \int_{0}^{x}\frac{1}{\sqrt{a^2 - b/x}}dx[/tex]

I have tried substituting 1/x with u and so on... But it doesn't seem to work :(

Thanks in advance!
 
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1/Sqrt(a^2 - b/x)
1/sqrt(a^2x - b)/Sqrt(x)
Sqrt(x)/ Sqrt(a^2x - b)
Let u = a^2x - b
du/dx = a^2
du/a^2 = dx
u+b/a^2 = x
Integral becomes - (1/a)Sqrt(u+b) * 1/Sqrt(u) * du/a^2
1/a^3 + 1/a^3sqrt(b/a) du
 
Thank you :)

(By the way, I think you meant 1/a^3[sqrt((u+b)/u)] for the last part, right?)
 

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