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I just dont get the idea on how to do this [projectile motion]

  1. May 1, 2012 #1
    i dont know how this works.....when a body is projected at an angle "theta" with the horizontal above a height 'h'...what is its maximum height and maximum range???should i just treat it as two separate motions or is there another way to do it....i can solve if it is just a parabolic projection from the ground or if it is horizontal projection from an height(parallel to the horizontal)

    please help???
     
  2. jcsd
  3. May 1, 2012 #2

    Ken G

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    Gold Member

    The preferred technique is to break the motion into two independent components, vertical and horizontal. You can write F=ma for the two componenents separately, and the only thing that connects them is they share the same "t" (time). Often, the horizontal (x) component is simply motion at a constant speed, x=vt. The vertical (y) component is the same as if you throw a particle straight up with some initial speed u. Then note that v and u are the components of the initial velocity, using trigonometry on the angle theta.
     
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