I just dont get the idea on how to do this [projectile motion]

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SUMMARY

The discussion focuses on solving projectile motion problems involving a body projected at an angle "theta" from a height "h." The preferred technique is to decompose the motion into two independent components: vertical and horizontal. The horizontal motion is treated as constant speed, while the vertical motion is analyzed using the equations of motion for vertical displacement. The initial velocity components can be determined using trigonometric functions based on the angle theta.

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  • Understanding of basic physics concepts, specifically Newton's second law (F=ma).
  • Knowledge of projectile motion equations and their applications.
  • Familiarity with trigonometry, particularly in resolving vectors into components.
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suryanarayan
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i don't know how this works...when a body is projected at an angle "theta" with the horizontal above a height 'h'...what is its maximum height and maximum range?should i just treat it as two separate motions or is there another way to do it...i can solve if it is just a parabolic projection from the ground or if it is horizontal projection from an height(parallel to the horizontal)

please help?
 
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The preferred technique is to break the motion into two independent components, vertical and horizontal. You can write F=ma for the two componenents separately, and the only thing that connects them is they share the same "t" (time). Often, the horizontal (x) component is simply motion at a constant speed, x=vt. The vertical (y) component is the same as if you throw a particle straight up with some initial speed u. Then note that v and u are the components of the initial velocity, using trigonometry on the angle theta.
 

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