I NEED IMMEDIATE HELP for solving the magnitude and direction of current

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Homework Help Overview

The discussion revolves around a problem involving two parallel wires, where one wire carries a known current and experiences a repulsive force due to the magnetic field created by the other wire. The objective is to determine the magnitude and direction of the current in the second wire based on the given parameters.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the left-hand and right-hand rules to determine the direction of the magnetic field and current. There are questions about the correct application of these rules and the relevance of the problem's placement in the forum.

Discussion Status

The discussion is ongoing, with participants providing various insights about the rules of electromagnetism and the formulas relevant to the problem. Some participants express uncertainty about the correct section for the post and the application of the rules, while others attempt to clarify the concepts involved.

Contextual Notes

There is mention of a formula for calculating the magnetic field and confusion regarding the application of different hand rules. Some participants indicate a lack of sufficient knowledge to assist further, highlighting the complexity of the topic.

Bk8907
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ok here's the prob.

Two parallel wires are 20cm apart. EAch wire is 1.5 m long. The wire on the left carries 10 A of current up. Find the magnitude and direction of the current of the wire on the right ir it is REPELLED WITH A FORCE OF 10N.

please help
 
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Appy Felmmings left hand rule
 
LEFT hand? I thought there was only RIGHT hand
 
Strech Left hand's First finger, forefinger n thumb

First Finger - direction of magnetic field
Middle Finger - Direction of current
Thumb - direction of force on the conductor/wire

Right hand is for Electromagnetic Induction EMI

Magnitude can be calculated by F=B.I.L (or BqV in case or a moving charged partile)
 
what? wrong section?
 
Questions like this belong in the homework help section.
 
ok, so from my problem, the current on the second wire is up (north) and what does B stand for again?
 
oh ok neo devin
 
  • #10
Addendum - Apply Right hand thumb rule to find direction of magnetic field around the wire carrying current where thumb is for direction of current and curled fingers are for magnetic filed( this is different from motor and dyanmo rule)
 
  • #11
so the current on the second wire IS north, but now with the 10N repulsion, how do i find magnitude?
 
  • #12
B is magnitude of the magnetic filed


B= \frac {u_0.I}{2 \pi r}

u_0 permeability of vacuum

(Dont have enough knowledge to assist in this context, sorry)
 
  • #13
wow what a formula! i use F=2K'I/r
 

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