I need some clarification for a high school vectors question (accelerating bird)

Click For Summary
SUMMARY

The discussion centers on calculating the initial velocity of a bird that accelerates at 2.82 m/s² north for 4.11 seconds, with a final velocity of 9.09 m/s east. Participants clarify that the average velocity should not be used for this calculation; instead, the final velocity is appropriate. The correct approach involves using the equation vf = v0 + a*t to determine the initial velocity, emphasizing the importance of separating vector components. Misunderstandings about the role of displacement in this context are also addressed.

PREREQUISITES
  • Understanding of vector components in physics
  • Familiarity with kinematic equations, specifically vf = v0 + a*t
  • Knowledge of the Pythagorean theorem for vector resolution
  • Basic trigonometry, including the tangent function for angle calculations
NEXT STEPS
  • Study the application of kinematic equations in two-dimensional motion
  • Learn how to resolve vectors into components for acceleration and velocity
  • Practice problems involving acceleration and initial velocity calculations
  • Explore the relationship between displacement, velocity, and acceleration in physics
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and vector analysis, as well as educators seeking to clarify concepts related to motion and acceleration.

Christopher Nguyen
Messages
7
Reaction score
2

Homework Statement


A bird flying in the air accelerates 2.82 m/s2 north for 4.11 seconds. the final velocity of the bird is 9.09 m/s [east]. What was the initial velocity of the bird?

Homework Equations


vf=v0+a*t

v(average)=(v0+vf)/2

v=d/t

d=v0t +½at2

tanθ=opp/adj

The Attempt at a Solution


[/B]
I turned the givens into vectors that resulted in the formation of a right angle triangle.

Used Pythagorean theorem to solve for the hypotenuse (initial velocity).

Used tangent to solve for the angle
Untitled.png

The one question I have is regarding the vector for acceleration that would be used: when turning the acceleration into a velocity (vector) would the final velocity or the average velocity be used?

I used the average velocity with the idea that if the final were used then it would be the same as if a constant vector were applied to the bird (which is not the case). Since the force varies the vector should only apply the final velocity at the end of the 4.11s.

Can someone help clarify if this is the wrong approach or not?

Thank you.

(edit: sorry for the Ms paint and thank you for the tips for formatting)
 

Attachments

  • Untitled.png
    Untitled.png
    7.5 KB · Views: 731
Last edited:
Physics news on Phys.org
You have just described in words what you did. In order to avoid misunderstandings, it is better if yoy also show your actual computations (also the intermediate steps).

A hint is that only your first relevant equation is actually relevant to your problem.
 
  • Like
Likes   Reactions: Christopher Nguyen
Christopher Nguyen said:

Homework Statement


A bird flying in the air accelerates 2.82 m/s2 north for 4.11 seconds. the final velocity of the bird is 9.09 m/s [east]. What was the initial velocity of the bird?

Homework Equations


vf=v0+a*t

v(average)=(v0+vf)/2

v=d/t

d=v0t +½at2

tanθ=opp/adj

The Attempt at a Solution


[/B]
I turned the givens into vectors that resulted in the formation of a right angle triangle.

Used Pythagorean theorem to solve for the hypotenuse (initial velocity).

Used tangent to solve for the angle

The one question I have is regarding the vector for acceleration that would be used: when turning the acceleration into a velocity (vector) would the final velocity or the average velocity be used?

I used the average velocity with the idea that if the final were used then it would be the same as if a constant vector were applied to the bird (which is not the case). Since the force varies the vector should only apply the final velocity at the end of the 4.11s.

Can someone help clarify if this is the wrong approach or not?

Thank you.

To answer your question, why would you use average velocity? What are you trying to calculate?

You have a quoted a number of equations, but you haven't indicated that these are vector equations, and you have not related them to separate vector components.
 
  • Like
Likes   Reactions: Christopher Nguyen
PeroK said:
To answer your question, why would you use average velocity? What are you trying to calculate?

You have a quoted a number of equations, but you haven't indicated that these are vector equations, and you have not related them to separate vector components.

Sorry about the lack of visuals. The question is about trying to solve for an initial velocity when it is accelerated by 2.82m/s2 for 4.11 seconds and whether the final velocity or average velocity should be used as the added component.
 
Christopher Nguyen said:
Sorry about the lack of visuals. The question is about trying to solve for an initial velocity when it is accelerated by 2.82m/s2 for 4.11 seconds and whether the final velocity or average velocity should be used as the added component.

Yes, and my question to you is why use average velocity?

Try some calculations with simpler numbers if you need to.
 
  • Like
Likes   Reactions: Christopher Nguyen
You have an acceleration to the North, and after 4.11 s you have a final velocity to the East. It is asking about the initial velocity. You might think about why there is no velocity to the North after the 4.11 s. Did the acceleration affect whatever initial velocity there was to the East?
 
  • Like
Likes   Reactions: Christopher Nguyen
PeroK said:
Yes, and my question to you is why use average velocity?

Try some calculations with simpler numbers if you need to.

I used the average velocity because the final velocity of the acceleration wouldn't be applied to the initial velocity for the entire duration of the 4.11s.

This idea could be misguided and I would like to know if it is and why.
 
Christopher Nguyen said:
I used the average velocity because the final velocity of the acceleration wouldn't be applied to the initial velocity for the entire duration of the 4.11s.

This idea could be misguided and I would like to know if it is and why.

Yes, it's misguided. Try this one. It's a 1D problem:

A bird accelerates at ##2m/s^2## for ##4s##. It's final velocity is ##8m/s##. What was its initial velocity?
 
  • Like
Likes   Reactions: Christopher Nguyen
sojsail said:
You have an acceleration to the North, and after 4.11 s you have a final velocity to the East. It is asking about the initial velocity. You might think about why there is no velocity to the North after the 4.11 s. Did the acceleration affect whatever initial velocity there was to the East?

the acceleration would have counteracted an initial component of the initial velocity that was towards the south would it not?

the acceleration doesn't affect the initial velocity to the east so that component still exists which is why the final velocity lies towards the east
 
  • #10
PeroK said:
Yes, it's misguided. Try this one. It's a 1D problem:

A bird accelerates at ##2m/s^2## for ##4s##. It's final velocity is ##8m/s##. What was its initial velocity?

v0=8-(2)(4)=0 m/s
 
  • Like
Likes   Reactions: PeroK
  • #11
Christopher Nguyen said:
v0=8-(2)(4)=0 m/s

So, you used the final velocty and not the average velocity.
 
  • Like
Likes   Reactions: Christopher Nguyen
  • #12
PeroK said:
So, you used the final velocty and not the average velocity.

I get it.

i additionally had a proof where i correlated velocity with displacement and converted all of the components with their respective displacement during the time period. (its definitely wrong because i got the same answer) could you help me fix that as well?
 
  • #13
Christopher Nguyen said:
I get it.

i additionally had a proof where i correlated velocity with displacement and converted all of the components with their respective displacement during the time period. (its definitely wrong because i got the same answer) could you help me fix that as well?

I'm not sure why you'd need displacement. It's a simple equation involving velocity and acceleration.
 
  • #14
PeroK said:
I'm not sure why you'd need displacement. It's a simple equation involving velocity and acceleration.

it was just a "proof", not part of the actual question. I thought since displacement and velocity were correlated with time i could use that fact to "prove" the solution i got.

JPEG_20190321_165122.jpg
 

Attachments

  • JPEG_20190321_165122.jpg
    JPEG_20190321_165122.jpg
    25.7 KB · Views: 596
  • #15
Christopher Nguyen said:
it was just a "proof", not part of the actual question. I thought since displacement and velocity were correlated with time i could use that fact to "prove" the solution i got.

View attachment 240619

Displacement has nothing to do with this problem. The problem is about velocities and acceleration. Attempting to introduce some type of displacement equation in order to prove something about velocity just indicates that you do not understand this problem---other problems, maybe, but not this one.
 
  • Like
Likes   Reactions: Christopher Nguyen

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K
Replies
13
Views
4K
  • · Replies 8 ·
Replies
8
Views
5K
Replies
2
Views
10K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K