I need some guidance on my coulomb's law homework.

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SUMMARY

The discussion focuses on solving a Coulomb's Law homework problem involving two charged particles, q1 (+3.0 μC) and q2 (-4.0 μC), positioned in the xy-plane. The user calculated the electrostatic force on q2 to be 0.025N at an angle of 144° counterclockwise but seeks confirmation of this result and guidance on the next steps. The distance formula d = √((x2 - x1)² + (y2 - y1)²) is highlighted as essential for determining the force between the charges. Additionally, the user inquires about the placement of a third charge, q3 (+4 μC), to achieve a net force of zero on q2.

PREREQUISITES
  • Coulomb's Law and its application in electrostatics
  • Vector addition of forces in two dimensions
  • Basic trigonometry for angle calculations
  • Distance formula in Cartesian coordinates
NEXT STEPS
  • Review the derivation of Coulomb's Law and its formula: F = k * |q1 * q2| / r²
  • Learn how to calculate the resultant force from multiple charges using vector addition
  • Study the concept of electric field and its relation to charge placement
  • Explore equilibrium conditions for charged particles in electrostatic systems
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Students studying electrostatics, physics educators, and anyone seeking to understand the principles of Coulomb's Law and force interactions between charged particles.

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Homework Statement


two charged particles held fixed in the xy plane are: q1= +3.0 μC, x1=3.5 cm, y1= 0.50 cm, and q2= -4.0 μC, x2= -2.0 cm, y2= 1.5 cm.

(question 1) What is the magnitude and the direction of the electrostatic force on q2. ?

(question 2) Where would a third charge q3= +4 μC be placed so that the net electrostatic force on q2 is zero?


Homework Equations


For question one i came out to 0.025N @144° ccw
is that even remotely correct?

The Attempt at a Solution


I don't want the answer, i would like to just know the steps so that i can try it for myself.
Ive added the x's amd y's and came out with

Ʃ x= 0.035-0.02= 0.015
Ʃ y= 0.005+0.015=.02

from here what can i do ?
could i just inverse the angle from q2 to find the position?
 
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Can you show your working for how you get 0.025N at 144o counterclockwise?
 
name of user said:

Homework Statement


two charged particles held fixed in the xy plane are: q1= +3.0 μC, x1=3.5 cm, y1= 0.50 cm, and q2= -4.0 μC, x2= -2.0 cm, y2= 1.5 cm.

(question 1) What is the magnitude and the direction of the electrostatic force on q2. ?

(question 2) Where would a third charge q3= +4 μC be placed so that the net electrostatic force on q2 is zero?


Homework Equations


For question one i came out to 0.025N @144° ccw
is that even remotely correct?

The Attempt at a Solution


I don't want the answer, i would like to just know the steps so that i can try it for myself.
Ive added the x's amd y's and came out with

Ʃ x= 0.035-0.02= 0.015
Ʃ y= 0.005+0.015=.02

from here what can i do ?
could i just inverse the angle from q2 to find the position?
Why are you adding the x coordinates and adding the y coordinates ?

The distance between points, (x1, y1) and (x2, y2) is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\ .
 

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