two charged particles held fixed in the xy plane are: q1= +3.0 μC, x1=3.5 cm, y1= 0.50 cm, and q2= -4.0 μC, x2= -2.0 cm, y2= 1.5 cm.
(question 1) What is the magnitude and the direction of the electrostatic force on q2. ?
(question 2) Where would a third charge q3= +4 μC be placed so that the net electrostatic force on q2 is zero?
For question one i came out to 0.025N @144° ccw
is that even remotely correct?
The Attempt at a Solution
I don't want the answer, i would like to just know the steps so that i can try it for myself.
Ive added the x's amd y's and came out with
Ʃ x= 0.035-0.02= 0.015
Ʃ y= 0.005+0.015=.02
from here what can i do ?
could i just inverse the angle from q2 to find the position?