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I want to check my answer if possible

  1. Dec 7, 2009 #1
    Hi all


    i want to check my answer if possible

    http://www.up-00.com/h1files/IEk98637.jpg [Broken]
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Dec 7, 2009 #2

    Mark44

    Staff: Mentor

    Your work is incorrect, with mistakes on almost every line.
    Line 2: You multiplied both fractions by the same expression. You need to multiply each fraction by something different.
    Line 3: cosx - cosx = 0 not 2cosx.
    Line 5: cosx != 1 - sinx
    Line 6: sin^2(x) - 1 != -(1 + sin^2(x))
    Line 7: -(1 + sin^2(x)) != sin^2(x) - 1
    Line 8: sin^2(x) - 1 != sinx
     
  4. Dec 7, 2009 #3
    thanks very much
     
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