The discussion revolves around a marble being released from a platform with a height described by a quadratic equation. The initial velocity of the marble is given, and participants are exploring the implications of the platform's height and velocity on the marble's motion.
There is an ongoing exploration of the relationship between the platform's height and the marble's motion. Some participants have offered guidance on differentiating the position equation to find velocity, while others are still seeking clarity on the problem's setup.
There is uncertainty regarding the nature of the platform's height and its relevance after the marble is released. The initial conditions and the equation provided are under scrutiny, with participants expressing confusion about the implications of these factors.
Is it vx= dxf/t?CWatters said:Welcome to the forum. Please don't delete the Homework template as it's there for a good reason.
In what direction is the marble released?
You have an equation for the height/position of the platform. Do you know how to get an equation for the velocity of an object from the equation for it's position?
I am not sure if the platform is at a fixed height. That's the whole the whole problem.FactChecker said:Your question confuses me. Is the platform at a fixed height of 70 meters or is it at a changing height of 2.3[t][/2]+ (-)6.5t+70? Also, why would the platform height matter after the marble is released?
DThes said:I am not sure if the platform is at a fixed height.
DThes said:Is it vx= dxf/t?
FactChecker said:Your question confuses me. Is the platform at a fixed height of 70 meters or is it at a changing height of 2.3[t][/2]+ (-)6.5t+70? Also, why would the platform height matter after the marble is released?
Oh, of course. Thanks.CWatters said:It's not the height that matters it's the velocity. I assume the launch velocity (22.5m/s) is relative to the moving platform.
Correction: The height at launch will matter but it's known to be 70m.
I assume that we are talking about an upward vertical release. So we are talking about vertical position -- aka height. We have the height of the platform as a function of time. We do not have anything that would aptly be called "x" or "f".DThes said:Is it vx= dxf/t?